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natali 33 [55]
3 years ago
11

Sarah has completed the first few steps for constructing the inscribed circle for triangle ABC. She started by constructing the

angle bisectors for angles A and C. This gives her the incenter (point D). What is the next step?
A) Construct the angle bisector for angle B.
B) Construct a circle with center D that passes through point B.
C) Construct the perpendicular bisector of one side of the triangle.
D) Construct the altitude from the incenter to a side of the triangle and label the intersection point.

Mathematics
2 answers:
mote1985 [20]3 years ago
8 0
Choice A. You want all three angle bisectors
frez [133]3 years ago
7 0

Answer:

The next step is to construct the altitude from the incentre  to a side of triangle and label the intersection point

Step-by-step explanation:

To construct the inscribed circle we have several steps of construction

Step 1: First step is to construct the incenter with the help of angle bisectors of two base vertices.

Step 2: After incenter, draw a line perpendicular to one side of triangle that passes through incenter and the label the point of intersection.

This is very important step because after labelling measure the radius(same as the distance between the incenter and labelled point) and draw the circle.

Hence, after incenter The next step is to construct the altitude from the incentre  to a side of triangle and label the intersection point.

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I'm so bad at math please anyone help :(
kondaur [170]
It should be d. , Because if you take the equation 3x+y=9, and make it slope intercept form, it would be y= -3x+9. -3 is the slope, and 9 is the y intercept. D is the answer.
6 0
2 years ago
121 bricks in 16.5 minutes 22 brings in m minutes
Westkost [7]
Use a proportion.

121/16.5 = 22/m

121m = 16.5 * 22

11m = 16.5 * 2

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4 0
3 years ago
The midpoint of gh is m(4,-3). One endpoint is G(-2,2). Find the coordinates of endpoint H
Mars2501 [29]

Answer:

Step-by-step explanation:

(-2 + x)/2= 4

-2 + x = 8

x = 10

(2 + y)/2 = -3

2 + y = -6

y = -8

(10, -8) for endpoint H

4 0
2 years ago
Can you help me with 7 and 8
elena55 [62]
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4 0
2 years ago
What are the real zeros of x^3+4x^2-9x-36
Katyanochek1 [597]

Answer:

x = -4\\x = -3\\x = 3

Step-by-step explanation:

To find the real zeros you must match the function to zero and factor the expression.

We have a polynomial of degree 3.

We try to group the terms to perform the factorization

x ^ 3 + 4x ^ 2-9x-36 = 0\\\\x ^ 2(x + 4) - 9(x + 4) = 0

Now we take (x + 4) as a common factor

(x + 4)(x ^ 2 -9) = 0

If we have an expression of the form (a ^ 2-b ^ 2) we know that this expression is equivalent to:

(a ^ 2-b ^ 2) = (a + b)(a-b)

In this case

a = x\\b = 3

So:

(x ^ 2 -9) = (x + 3)(x-3)

Finally:

x ^ 3 + 4x ^ 2-9x-36 = (x + 4)(x + 3)(x-3) = 0

The solutions are:

x = -4\\x = -3\\x = 3

6 0
3 years ago
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