<u><em>Answer:</em></u>
∠BOY = 38°
<u><em>Explanation:</em></u>
<u>From the diagram, we can note that:</u>
m∠TOY = m∠TOB + m∠BOY ...................> equation I
We are given that ray OB bisects the angle
<u>Therefore:</u>
m∠TOB = m∠BOY
<u>Substitute in equation I:</u>
m∠TOY = m∠TOB + m∠TOB = 2m∠TOB ............> equation II
<u>We are given that:</u>
m∠TOY = 8x-36
m∠TOB = x+24
<u>Substitute with the givens in equation II and solve for x:</u>
m∠TOY = 2m∠TOB
8x - 36 = 2(x + 24)
2(4x-18) = 2(x+24)
4x - 18 = x + 24
3x = 42
x = 14
<u>This means that:</u>
m∠TOB = x + 24 = 14 + 24 = 38°
<u>Since </u>
m∠TOB = m∠BOY
<u>Therefore:</u>
m∠BOY = 38°
<u>Check:</u>
m∠TOY = 8x - 36 = 8(14) - 36 = 76° which is twice m∠TOB
Hope this helps :)
Answer:
72.3
Step-by-step explanation:
Given that:
The arithmetic sequence:

The first term of the sequence
= 3 since k = 0
i.e (3 + 0.26(0)) = 3
The last term of the sequence
= 6.64
i.e (3+ 0.26(14)
= (3 + 3.64)
= 6.64
Total no of terms = 15 i.e from 0 to 14
∴
The partial sum of the arithmetic sequence = 

= 72.3
Ur answer is. 5 y^2+4y+14 because I went through it in class
Step-by-step explanation:
![\sqrt[?]{?}](https://tex.z-dn.net/?f=%20%5Csqrt%5B%3F%5D%7B%3F%7D%20)
x m