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3 years ago

Please help with the question in the picture!

Mathematics

1 answer:

snow_lady [41]3 years ago

8 0

Answer:

EF is 1.98

Explanation:

For right triangles, you solve for sides and angles using the trig. ratios. You remember then with the acronym SohCahToa.

It is read as:

Sine is opposite over hypotenuse.

Cosine is adjacent over hypotenuse.

Tangent is opposite over adjacent.

Which side is opposite or adjacent depends on which angle is the angle of reference, the angle you are talking about. The adjacent side touches the angle of reference.

In this problem, angle D can be the angle of reference.

Since we know DF the hypotenuse, and we are looking for EF, the opposite side, we should use the Sine ratio.

sin D = sin 26° ≈ 0.44

sin D = EF/DF = EF/4.5

Substitute sinD for 0.44 and then isolate EF.

0.44 = EF/4.5

0.44(4.5) = EF Multiply both sides by 4.5

EF = 1.98

The measurement of EF is 1.98.

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Compound probability can be greater than 1. Trueor False?

vivado [14]

Answer:

False

Step-by-step explanation:

Compound probability is the likeliness of two or more events occurring together.

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If we get the answer of any question where the found probability is greater than 1 the answer is wrong because probability is not greater than 1.

The sum of all probabilities may be nearly equal to 1 like 0.99999 etc.

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4 years ago

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bagirrra123 [75]

A. Median number is the middle number. We can cross one off from left to right to get 4.
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4 years ago

Use a proof by contradiction to show that the square root of 3 is national You may use the following fact: For any integer kirke

Ierofanga [76]

Answer:

1. Let us proof that √3 is an irrational number, using reductio ad absurdum. Assume that $\sqrt{3}=\frac{m}{n}$ where $m$ and $n$ are non negative integers, and the fraction $\frac{m}{n}$ is irreducible, i.e., the numbers $m$ and $n$ have no common factors.

Now, squaring the equality at the beginning we get that

$3=\frac{m^2}{n^2}$ (1)

which is equivalent to $3n^2=m^2$ . From this we can deduce that 3 divides the number $m^2$ , and necessarily 3 must divide $m$ . Thus, $m=3p$ , where $p$ is a non negative integer.

Substituting $m=3p$ into (1), we get

$3= \frac{9p^2}{n^2}$

which is equivalent to

$n^2=3p^2$ .

Thus, 3 divides $n^2$ and necessarily 3 must divide $n$ . Hence, $n=3q$ where $q$ is a non negative integer.

Notice that

$\frac{m}{n} = \frac{3p}{3q} = \frac{p}{q}$ .

The above equality means that the fraction $\frac{m}{n}$ is reducible, what contradicts our initial assumption. So, $\sqrt{3}$ is irrational.

2. Let us prove now that the multiplication of an integer and a rational number is a rational number. So, $r\in\mathbb{Q}$ , which is equivalent to say that $r=\frac{m}{n}$ where $m$ and $n$ are non negative integers. Also, assume that $k\in\mathbb{Z}$ . So, we want to prove that $k\cdot r\in\mathbb{Z}$ . Recall that an integer $k$ can be written as

$k=\frac{k}{1}$ .

Then,

$k\cdot r = \frac{k}{1}\frac{m}{n} = \frac{mk}{n}$ .

Notice that the product $mk$ is an integer. Thus, the fraction $\frac{mk}{n}$ is a rational number. Therefore, $k\cdot r\in\mathbb{Q}$ .

3. Let us prove by reductio ad absurdum that the sum of a rational number and an irrational number is an irrational number. So, we have $x$ is irrational and $p\in\mathbb{Q}$ .

Write $q=x+p$ and let us suppose that $q$ is a rational number. So, we get that

$x=q-p$ .

But the subtraction or addition of two rational numbers is rational too. Then, the number $x$ must be rational too, which is a clear contradiction with our hypothesis. Therefore, $x+p$ is irrational.

7 0

4 years ago

Can some one help me with this question its hard :( down below ill give brainliest

Andreyy89

I think it’s the second one b

I hope this helps :)

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3 years ago

What is 19284x183x0x10=?

nasty-shy [4]

The answer is 0. Anything times 0 is zero.

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3 years ago