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3 years ago

Due Wed

Mathematics

2 answers:

erastovalidia [21]3 years ago

4 0

Answer:

d=2+2h

Step-by-step explanation:

the first two is how far she is already

the second two and h is 2mph

it equals d because the equation equals the total distance

Doss [256]3 years ago

3 0

Y=2x+2

Hope this helps

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Please help me with this and thank you

hichkok12 [17]

Answer:

16/3 or 5 1/3

Step-by-step explanation:

Because 2/3 * 8 = 16/3.

16/3 simplified is 5 1/3

4 0

3 years ago

Read 2 more answers

Nicole needs to spend at least 4 hours each week practicing the guitar. She has already practiced 2 1/3 hours this week. She wan

melisa1 [442]

Answer:

x>=5/6

Step-by-step explanation:

She's practiced 2 1/3 hours already. Therefore, she has 1 2/3 hours left to practice. Let x be the minimum number of hours she needs to practice on each of the remaining two days.

Splitting up the remaining hours into two days, we get (5/3) divided by 2, which is 5/6 hours per day.

x is greater than or equal to 5/6 hours per day.

7 0

3 years ago

Read 2 more answers

I need help with these two please :’)

tatiyna

Answer:

59)

Therefore the height of the pyramid is 14 meter.

60)

Therefore the Diameter of Cone is 17.32 cm.

Step-by-step explanation:

59 )

Given:

Shape is Rectangular Pyramid,

Length = 3 meter

Width = 8 meter

Volume of Rectangular Pyramid = 112 cubic meter

To Find:

Height:

Solution:

We Know,

$\textrm{Volume of Rectangular Pyramid}=\frac{1}{3}(Length\times Width\times Height)$

Substituting the given values we have

$112=\frac{1}{3}(3\times 8\times Height)\\ \\\therefore Height=\frac{336}{24}\\\\\therefore Height=14\ meter\\$

Therefore the height of the pyramid is 14 meter.

60 )

Thee shape is of Cone

Given:

Height= 5 cm

Volume of cone = 125 π cm³

To Find:

Diameter of a cone = d = ?

Solution:

We know,

$\textrm{Volume of cone}=\frac{1}{12}\pi (Diameter) ^{2}\times Height$

Substituting the given values we have

$125\pi =\frac{1}{12}\pi d^{2}\times 5\\ \\d^{2}=25\times 12\\ \\d^{2}=300\\\\d=17.32\\ \therefore Diameter = 17.32\ cm$

Therefore the Diameter of Cone is 17.32 cm.

6 0

3 years ago

A train leaves little rock Arkansas, travels north at 85 kilometers per hour. another train leaves same time and travels south a

iragen [17]

Hi,

Let us denote first train with T₁, its distance d₁, its speed v₁ = 85 km/h.

Similarly, second train would be with T₂, its distance d₂, its speed v₂ = 80 km/h. Also, let d be total distance, d = 495 km.

Given being the fact that train T₁ travels north, and train T₂ travels south, their path is on a straight vertical line. Please create a simple drawing, you will see the vertical line immediately.

Then, we need to find the time t, when d₁ + d₂ = d = 495 km (1)

Each speed v₁, and v₂ is constant, therefore we apply very well known formula:

d₁ = v₁·t, and d₂ = v₂·t (2).

From (1) and (2) we have:

v₁·t + v₂·t = d, or (v₁ + v₂)t = d ⇒ t = d/(v₁ + v₂) = 495/(80 + 85) = 495/165 = 3 hours.

So, it takes 3 hours to have those 2 trains 495 km apart.

Green eyes.

6 0

3 years ago

100 random students are surveyed outside of the student center on campus. Let V denote that the student has a Visa credit card a

mote1985 [20]

Answer:

(a) The value of P (M | V) is 0.30.

(b) The value of $P (M^{c} | V)$ is 0.70.

(d) The value of $P(V^{c}|M)$ is 0.625.

Step-by-step explanation:

It is provided that,

V = a student has a Visa card

M = a student has a Master card

N = 100, n (V) = 40, n (M) = 32 and n (V ∩ M) = 12.

The probability of a student having visa card is:

$P(V) = \frac{n(V)}{N}= \frac{40}{100}=0.40$

The probability of a student having master card is:

$P(M) = \frac{n(M)}{N}= \frac{32}{100}=0.32$

The probability of a student having visa card and a master card is:

$P(V\cap M) = \frac{n(V\cap M)}{N}= \frac{12}{100}=0.12$

The conditional probability of an event, say A, given that another event, say B, has already occurred is,

$P(A|B)=\frac{P(A\cap B)}{P(B)}$

(a)

Compute the probability that a student has a master card given that he/she has a visa card also, i.e. P (M | V) as follows:

$P(M|V)=\frac{P(V\cap M)}{P(V)} =\frac{0.12}{0.40}=0.30$

Thus, the value of P (M | V) is 0.30.

(b)

Compute the probability that a student does not have a master card given that he/she has a visa card also, i.e. $P (M^{c} | V)$ as follows:

$P (M^{c} | V)=1-P(M|V)=1-0.30=0.70$

Thus, the value of $P (M^{c} | V)$ is 0.70.

(c)

Compute the probability that a student has a visa card given that he/she has a master card also, i.e. P (V | M) as follows:

$P(V|M)=\frac{P(V\cap M)}{P(M)} =\frac{0.12}{0.32}=0.375$

Thus, the value of P (V | M) is 0.375.

(d)

Compute the probability that a student does not have a visa card given that he/she has a master card also, i.e. $P(V^{c}|M)$ as follows:

$P(V^{c}|M)=1-P(V|M)=1-0.375=0.625$

Thus, the value of $P(V^{c}|M)$ is 0.625.

8 0

3 years ago