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Sindrei [870]
3 years ago
13

2. What is 355% of 15?

Mathematics
2 answers:
Studentka2010 [4]3 years ago
7 0

Answer: 53.25

Step-by-step explanation:

sveticcg [70]3 years ago
6 0

Answer:

53.25 rounded to 53.0

Step-by-step explanation:

multiply

message me if need more help

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What is this question?? (needing help)
Free_Kalibri [48]

468 x 0.001 = 0.468

46.8 x 0.1 = 4.68

4.68 x 10^3 = 4680

0.468 x 10^2 = 46.8

Hope this helps!

5 0
3 years ago
Read 2 more answers
Ms. Velez will use both x gray bricks and y red bricks to build a wall around her garden. Gray bricks cost $0.45 each and red br
Finger [1]

Let

x--------> the number of gray bricks

y--------> the number of red bricks

we know that

y < \frac{x}{2} ------> inequality 1

0.45x+0.58y \leq 200 <em>-----> </em>inequality 2

therefore

<u>the answer is</u>

x > 0

0.45x+0.58y≤200

6 0
3 years ago
COULD YOU GUYS HELP ME WITH 6 AND 7 PLEASE
d1i1m1o1n [39]

Answer:

<em>Answer</em><em> </em><em>is</em><em> </em><em>given below with explanations</em><em>. </em>

Step-by-step explanation:

type \: 1 \: MSD \: s \: appropriate \: length  :  \\ vessels \: equal \: to \: or \: less \: than \:   \: 65 \:  \\ feet \: in \: length \\ option \: a) \: is \: the \: correct \: answer. \\ type \: 2 \: MSD \: s \: appropriate \: length   \\ vessels \: that \: are \: greater \: than \: 65 \:  \\ feet \: in \: length. \\ note  : Vessels 65 \: feet \:  or  less in length  \\ may use a Type I, II, or III MSD.  \\ Vessels more than 65 feet in length must \\  install a Type II or III MSD.

<em>HAVE </em><em>A NICE DAY</em><em>!</em>

<em>THANKS FOR GIVING ME THE OPPORTUNITY</em><em> </em><em>TO ANSWER YOUR QUESTION</em><em>.</em>

7 0
3 years ago
The boundary of a park is shaped like a circle. The park has a rectangular playground in the center and 2 square flower beds, on
fiasKO [112]

Answer:

Step-by-step explanation:

Get the perimeter of the each shape and add it all up to get the total fencing material required.

2 square flower beds = 2 x 4a = 8a

1 rectangular play ground = 2l + 2w 

total fencing material = 8a + 2l + 2w

7 0
3 years ago
Geometry problem help!<br><br> Please refer to the image below...
Vinil7 [7]

Answer:

A. 1/3

B. √10

C. -1, 1

D. √8, 6

E. congruent and opposite pairs parallel

F. perpendicular, not congruent

G. rhombus, explanation below

Step-by-step explanation:

Hey there! I'm happy to help!

-----------------------------------------------------------------

A.

Slope is the rise over the run. Let's look at F to G.

We are going from -1 to 2 on our x-axis (run), so our run is 3 units.

Our rise is 1 unit as we go from 2 to 3 on the y-axis.

slope=\frac{rise}{run} =\frac{1}{3}

This slope is the same for all of the sides.

-----------------------------------------------------------------

B.

We will use the distance formula (which is basically just the Pythagorean Theorem) to calculate the length of each side. Let's go between F and G again, but this distance is the same for all the sides.

\sqrt{(x_{2}-x_1)^2+(y_{2}-y_1)^2 } \\\\(x_1,y_1)=(-1,2)\\\\(x_2,y_2)=(2,3)\\\\\\\sqrt{(2+1)^2+(3-2)^2 } \\\\\sqrt{(3)^2+(1)^2 }\\\\\sqrt{9+1 }\\\\\sqrt{10}

-----------------------------------------------------------------

C.

The diagonals are the lines that connect the non-adjacent vertices.

Our two diagonals are FH and GE.

-----------------------------

<u>FH</u>

We go from x-value -1 to 1 from F to H, so our run is 2.

We go from y-value 2 to 0. so our rise is -2.

slope=\frac{rise}{run} =-\frac{2}{2} =-1

-----------------------------

<u>GE</u>

We go from x-value -2 to 2 from E to G, so our run is 4.

We go from y-value -1 to 3. so our rise is 4.

slope=\frac{rise}{run} =\frac{4}{4} =1

-----------------------------------------------------------------

D.

Let's use the distance formula on each of our diagonals.

-----------------------------

<u>FH</u>

<u />\sqrt{(x_{2}-x_1)^2+(y_{2}-y_1)^2 } \\\\(x_1,y_1)=(-1,2)\\\\(x_2,y_2)=(1,0)\\\\\\\sqrt{(1+1)^2+(0-2)^2 } \\\\\sqrt{(2)^2+(-2)^2 }\\\\\sqrt{4+4 }\\\\\sqrt{8}<u />

-----------------------------

<u>GE</u>

\sqrt{(x_{2}-x_1)^2+(y_{2}-y_1)^2 } \\\\(x_1,y_1)=(-2,-1)\\\\(x_2,y_2)=(2,3)\\\\\\\sqrt{(2+2)^2+(3+1)^2 } \\\\\sqrt{(4)^2+(4)^2 }\\\\\sqrt{16+16 }\\\\\sqrt{36}\\\\6

-----------------------------------------------------------------

E.

They are congruent as they all have the same length (√10) and the opposite sides are parallel as they have the same slope (1/3)

-----------------------------------------------------------------

F.

They are perpendicular diagonals as their slopes are negative reciprocals (1 and -1), and they are not congruent as they have different lengths (√8 and 6).

-----------------------------------------------------------------

G.

<u>Parallelogram-</u> quadrilateral with opposite pairs of parallel sides.

<u>Rhombus-</u> a parallelogram with four equal sides

<u>Square-</u> a rhombus with four right angles

We can see that this is a parallelogram as we saw that the opposite sides are parallel due to having the same slope, and the perpendicular diagonals show that as well. This is also a rhombus because if we use that distance formula on all the sides, it will be the same. It is not a square though because it does not have four right angles, so this is a rhombus.

-----------------------------------------------------------------

Have a wonderful day and keep on learning!

8 0
3 years ago
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