Because the triangles are congruent we know that NM = ST = 50.
answer: 50
Answer:
17 seconds
Step-by-step explanation:
Solution:-
The trajectory of a rocket launched is modeled by a parabolic path via a quadratic equation as follows:

Where,
y: The height of the rocket from ground
x: The time taken since rocket launch
We are to determine the time ( x ) it takes for the rocket to hit the ground. This can be determined by setting the quantity ( y ) to zero as follows

solve the quadratic equation using quadratic formula as follows:

Answer: Ignore the negative value for time " -0.375 ". Hence, the rocket hits the ground at time t = 17 seconds
Answer:
a=38
b=45
c=38
d=105
e=45
Step-by-step explanation:
The easiest variable you can solve for first is "z". Knowing that opposite angles of a quadrilateral inscribed in a circle are supplementary, subtract 93 from 180 to get z.
Z should equal 87.
The next variable we can solve for is "x". We know that inscribed angles are half the measure of their intercepting arc, so we know 93 is half of (112 + x). The equation would look like this:
93= (112 + x)/2
Multiply both sides by 2
186 = 112 + x
Subtract 112 from both sides
74 = x
Now we can apply the same method we used to find "x" to find y. Set up an equation like this:
80 = (y + x)/2
Substitute the value of x in
80 = (y + 74)/2
Multiply both sides by 2
160 = y + 74
Subtract 74 from both sides
86 = y
Hope this helps!