No personal web..............
Answer:
a. Password length, password encryption, password complexity
Explanation:
Under this scenario, the best combination would be Password length, password encryption, password complexity. This is because the main security problem is with the user's passwords. Increasing the password length and password complexity makes it nearly impossible for individuals to simply guess the password and gain access, while also making it extremely difficult and time consuming for hackers to use software to discover the password as well. Password excryption would be an extra layer of security as it encrypts the password before storing it into the database, therefore preventing eavesdroppers from seeing the password and leaked info from being used without decryption.
Answer:
// code in C++
#include <bits/stdc++.h>
using namespace std;
// main function
int main()
{
// variables
int sum_even=0,sum_odd=0,eve_count=0,odd_count=0;
int largest=INT_MIN;
int smallest=INT_MAX;
int n;
cout<<"Enter 10 Integers:";
// read 10 Integers
for(int a=0;a<10;a++)
{
cin>>n;
// find largest
if(n>largest)
largest=n;
// find smallest
if(n<smallest)
smallest=n;
// if input is even
if(n%2==0)
{
// sum of even
sum_even+=n;
// even count
eve_count++;
}
else
{
// sum of odd
sum_odd+=n;
// odd count
odd_count++;
}
}
// print sum of even
cout<<"Sum of all even numbers is: "<<sum_even<<endl;
// print sum of odd
cout<<"Sum of all odd numbers is: "<<sum_odd<<endl;
// print largest
cout<<"largest Integer is: "<<largest<<endl;
// print smallest
cout<<"smallest Integer is: "<<smallest<<endl;
// print even count
cout<<"count of even number is: "<<eve_count<<endl;
// print odd cout
cout<<"count of odd number is: "<<odd_count<<endl;
return 0;
}
Explanation:
Read an integer from user.If the input is greater that largest then update the largest.If the input is smaller than smallest then update the smallest.Then check if input is even then add it to sum_even and increment the eve_count.If the input is odd then add it to sum_odd and increment the odd_count.Repeat this for 10 inputs. Then print sum of all even inputs, sum of all odd inputs, largest among all, smallest among all, count of even inputs and count of odd inputs.
Output:
Enter 10 Integers:1 3 4 2 10 11 12 44 5 20
Sum of all even numbers is: 92
Sum of all odd numbers is: 20
largest Integer is: 44
smallest Integer is: 1
count of even number is: 6
count of odd number is: 4
Answer:
1 Array languages
2 Assembly languages
3 Authoring languages
4 Constraint programming languages
5 Command line interface languages
6 Compiled languages
7 Concurrent languages
8 Curly-bracket languages
9 Dataflow languages
10 Data-oriented languages
11 Decision table languages
12 Declarative languages
13 Embeddable languages
13.1 In source code
13.1.1 Server side
13.1.2 Client side
13.2 In object code
14 Educational languages
15 Esoteric languages
16 Extension languages
17 Fourth-generation languages
18 Functional languages
18.1 Pure
18.2 Impure
19 Hardware description languages
19.1 HDLs for analog circuit design
19.2 HDLs for digital circuit design
20 Imperative languages
21 Interactive mode languages
22 Interpreted languages
23 Iterative languages
Explanation:
Cyberbullying overlaps with discriminatory harassment
