Let p be 0.831 denote the percentage of defective welds and q be 0.169 denote the percentage of non-defective welds.
Using the binomial distribution, we want all three to be defective.


They can travel 110 miles for 5 gallons of gas.
22 • 5 = 110 miles on 5 gallons of gas
Answer:
Yes
Step-by-step explanation:
If we where to simplfy the 4(5d - 4) it would be 20d - 16 and that is equivalent to 20d - 16.