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Aleks [24]
3 years ago
8

Please i need help 15 points Please answer both

Mathematics
1 answer:
ki77a [65]3 years ago
5 0

Answer:

5a. x = 15

5b. z = 125

Step-by-step explanation:

Please see attached photo.

y° = 4x – 5... (1) (Alternate angles are equal)

y° = 5x – 20. (2) (opposite angles are equal)

5a. Determination of the value of x.

We can obtain the value of x by equating equation 1 and 2 as shown below

y° = 4x – 5.... (1)

y° = 5x – 20... (2)

y° = y°

5x – 20 = 4x – 5

Collect like terms

5x – 4x = – 5 + 20

x = 15

5b. Determination of the value of z.

The value of z can be obtained as follow:

4x – 5 + z = 180 (angle on a straight line).

x = 15

4(15) – 5 + z = 180

60 – 5 + z = 180

55 + z = 180

Collect like terms

z = 180 – 55

z = 125

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Answer:

I=7000C

Step-by-step explanation:

Let C represent number of dairy cows.  

We have been given that each dairy cow produces 3500 gallons of milk per year. So amount of milk produced by C cows in 1 year would be 3500C gallons.

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6 0
3 years ago
Will give brainliest answer
Alik [6]

Answer:

Below.

Step-by-step explanation:

log  10  ( 100 )  =  2

5 0
3 years ago
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Two column proofs Beginner's
Darina [25.2K]

LETS prove the 2nd part of the Question

Here concept of right angles is used

We can see BA is perp to BD

and BC is perp to BE

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as BA is perp to BD hence angle between them will be 90 degree

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3 0
1 year ago
Solve.
Nikitich [7]
The answer is C: 10\text{ }^1/_2. Here are the details:

\text{Equation:}\\ 6\text{ }^1/_3+10\text{ }^1/_2\stackrel{?}{=}26\text{ }^1/_6\\ \\ \text{Start with the integers.}\\ 6+10=16\stackrel{?}{=}26\text{ }^1/_6\\ \\ \text{...then with the fractions, but rewrite them first to make it easier.}\\ ^1/_3+\text{ }^1/_2\stackrel{\text{rewrite}}{\to}\text{ }^2/_6+\text{ }^3/_6=\text{ }^5/_6\stackrel{?}{=}26\text{ }^1/_6\\
\\
\text{Add 'em up!}\\
16\text{ }^5/_6

\text{Equation:}\\
16\text{ }^5/_6+3\text{ }^5/_6\stackrel{?}{=}26\text{ }^1/_6\\
\\
\text{Start with the integers.}\\
16+3=19\stackrel{?}{=}26\text{ }^1/_6\\
\\
\text{...then with the fractions, but rewrite them first to make it easier.}\\
^5/_6+\text{ }^5/_6=\text{ }^{10}/_6\stackrel{\text{rewrite}}{\to}\text{ }^5/_3\stackrel{\text{rewrite}}{\to}1\text{ }^2/_3\stackrel{?}{=}26\text{ }^1/_6\\
\\
\text{Add 'em up!}\\
20\text{ }^2/_3

\text{Last equation:}\\ 20\text{ }^2/_3+5\text{ }^1/_2\stackrel{?}{=}26\text{ }^1/_6\\ \\ \text{Start with the integers.}\\ 20+5=25\stackrel{?}{=}26\text{ }^1/_6\\ \\ \text{...then with the fractions, but rewrite them first to make it easier.}\\ ^2/_3+\text{ }^1/_2\stackrel{\text{rewrite}}{\to}\text{ }^4/_6+\text{ }^3/_6=\text{ }^7/_6\stackrel{\text{rewrite}}{\to}1\text{ }^1/_6\stackrel{?}{=}26\text{ }^1/_6\\
\\
\text{Add the integer and fraction together.}\\
25+1\text{ }^1/_6\stackrel{?}{=}26\text{ }^1/_6

26\text{ }^1/_6\stackrel{\checkmark}{=}26\text{ }^1/_6
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Answer:

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