Find two positive numbers whose difference is 8 and whose product is 1505.

Mathematics

1 answer:

likoan [24]3 years ago

6 0

Answer:

The two positive numbers are 35 and 43.

Step-by-step explanation:

Let the two positive numbers be x and x + 8.

It is given that their product is 1505.

Therefore, x(x + 8) = 1505

$x^{2} +8x=1505$

$x^{2} +8x-1505=0$

$x^{2} +43x-35x-1505=0$

x(x + 43) - 35(x + 43) = 0

(x + 43)(x - 35) = 0

x = -43, x = 35

Since, the numbers are positive, x = 35 is only valid.

The other number is x + 8 = 35 + 8 = 43.

Hence, the required positive numbers are 35 and 43.

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Answer:

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Step-by-step explanation:

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The coefficients are the constant multiplier of the term. Some say a "constant", such as the -8 in the last expression, is not considered a coefficient, because there are no variables that it is multiplying. Here, we have listed it among the coefficients in that expression.

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