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3 years ago

Find two positive numbers whose difference is 8 and whose product is 1505.

Mathematics

1 answer:

likoan [24]3 years ago

6 0

Answer:

The two positive numbers are 35 and 43.

Step-by-step explanation:

Let the two positive numbers be x and x + 8.

It is given that their product is 1505.

Therefore, x(x + 8) = 1505

$x^{2} +8x=1505$

$x^{2} +8x-1505=0$

$x^{2} +43x-35x-1505=0$

x(x + 43) - 35(x + 43) = 0

(x + 43)(x - 35) = 0

x = -43, x = 35

Since, the numbers are positive, x = 35 is only valid.

The other number is x + 8 = 35 + 8 = 43.

Hence, the required positive numbers are 35 and 43.

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3 years ago

Jeremy measured the room to be 10 feet long and 4.5 feet wide. He plans to purchase carpet for the entire room. The carpet cost

Andreyy89

Answer:

$205.73

Step-by-step explanation:

First we find the square area,

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3 years ago

Convert 3.521 g to ___ mg

inna [77]

To convert any unit to it's "milli-" form always multiply the given value by 1000. The new value will be the value of in the "milli-" form.

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$3.521\times 1000=3521$ mg

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3 years ago

Read 2 more answers

The one-to-one functions g and h are defined as follows

Debora [2.8K]

Answer:

$g^-^1(x)=-8$

$h^-^1(x)=\frac{x-4}{3}$

$(h^-^1 \ o\ h)(-3)=-3$

Step-by-step explanation:

When given the following functions,

$g=[(-2,-7),(4,6),(6,-8),(7,4)]$

$h(x)=3x+4$

One is asked to find the following,

1. Question 1

$g^-^1(4)$

When finding the inverse of a function that is composed of defined points, one substitutes the input given into the function, then finds the output. After doing so, one must substitute the output into the function, and find its output. Thus, finding the inverse of the given input;

$g^-^1(4)$

$g(4)=6\\g(6)=-8\\g^-^1(4)=-8$

2. Question 2

$h^-^1(x)$

Finding the inverse of a continuous function is essentially finding the opposite of the function. An easy trick to do so is to treat the evaluator (h(x)) like another variable. Solve the equation for (x) in terms of (h(x)). Then rewrite the equation in inverse function notation,

$h(x)=3x+4\\\\h(x)-4=3x\\\\\frac{h(x)-4}{3}=x\\\\\frac{x-4}{3}=h^-^1(x)$

$h^-^1(x)=\frac{x-4}{3}$

3. Question 3

$(h^-^1 \ o\ h)(-3)$

This question essentially asks one to find the composition of the function. In essence, substitute function (h) into function ( $h^-^1$ ) and simplify. Then substitute (-3) into the result.