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irakobra [83]
3 years ago
13

HELP plz! Select yes or no for each.

Mathematics
1 answer:
rodikova [14]3 years ago
7 0

Answer:

no

no

yes

Step-by-step explanation:

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(39 points PLZ HELP)Find the sum of a finite geometric series. A ball is dropped from a height of 10 meters. Each time it bounce
erastovalidia [21]

So we need to find the sum of the first 5 terms.

You have told me that the first term is 10 meters, and that r = 0.5 per term.

With this knowledge, we can use the formula s_n=a₁((1-r^n)/(1-r)).

Plugging in the terms that we know...

s₅=10((1-0.5⁵)/(1-0.5))

s₅=10(0.96875/0.5)

s₅=10(1.9375)

s₅=19.375

With s₅, we can determine that the ball has traveled a total of 19.375 meters after 5 bounces.

3 0
3 years ago
Read 2 more answers
Pls help answer ASAP I will give Brainlyist
oksian1 [2.3K]

Answer:

B

Step-by-step explanation:

4 0
3 years ago
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Which of the sums below can be expressed as 6(3 + 9)? (3 points) 18 + 54 18 + 9 9 + 15 6 + 54
vitfil [10]

6*3 = 18

6*9 = 54

so 18 +54 is the correct answer

7 0
3 years ago
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If A and B are independent events, P(A) = 0.25, and P(B) = 0.3, what is P(AB)?
Marrrta [24]

Answer:

P(A) = 0.25, P(B= 0.3

And if we want to find P(A \cap B) we can use this formula from the definition of independent events :

P(A \cap B) =P(A) *P(B) = 0.25*0.3= 0.075

And the best option would be:

P(A \cap B) =0.075

Step-by-step explanation:

For this case we have the following events A and B and we also have the probabilities for each one given:

P(A) = 0.25, P(B= 0.3

And if we want to find P(A \cap B) we can use this formula from the definition of independent events :

P(A \cap B) =P(A) *P(B) = 0.25*0.3= 0.075

And the best option would be:

P(A \cap B) =0.075

3 0
3 years ago
Jim wants to build a rectangular parking lot along a busy street but only has 2400 feet of fencing available. if no fencing is r
PSYCHO15rus [73]
<span>Length = 1200, width = 600
   First, let's create an equation for the area based upon the length. Since we have a total of 2400 feet of fence and only need to fence three sides of the region, we can define the width based upon the length as: W = (2400 - L)/2
   And area is: A = LW
    Substitute the equation for width, giving: A = LW A = L(2400 - L)/2
    And expand: A = (2400L - L^2)/2 A = 1200L - (1/2)L^2
    Now the easiest way of solving for the maximum area is to calculate the first derivative of the expression above, and solve for where it's value is 0. But since this is supposedly a high school problem, and the expression we have is a simple quadratic equation, we can solve it without using any calculus. Let's first use the quadratic formula with A=-1/2, B=1200, and C=0 and get the 2 roots which are 0 and 2400. Then we'll pick a point midway between those two which is (0 + 2400)/2 = 1200. And that should be your answer. But let's verify that by using the value (1200+e) and expand the equation to see what happens:
   A = 1200L - (1/2)L^2
 A = 1200(1200+e) - (1/2)(1200+e)^2
 A = 1440000+1200e - (1/2)(1440000 + 2400e + e^2)
 A = 1440000+1200e - (720000 + 1200e + (1/2)e^2)
 A = 1440000+1200e - 720000 - 1200e - (1/2)e^2
 A = 720000 - (1/2)e^2
   And notice that the only e terms is -(1/2)e^2. ANY non-zero value of e will cause this term to be non-zero and negative meaning that the total area will be reduced. Therefore the value of 1200 for the length is the best possible length that will get the maximum possible area.</span>
7 0
4 years ago
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