UGH I think I did this before but I totally forgot how to do it. Give me a minute to do some research and remember because I'm about 79% sure I know how to do this!
Answer:
The exponential growth formula.
The sales tax is 6.25% from $100
<h2>INVERSE VARIATION</h2>
<em>E</em><em>Q</em><em>U</em><em>A</em><em>T</em><em>I</em><em>O</em><em>N</em><em>:</em><em> </em><em> </em><em> </em><em> </em>
<em>–</em><em>–</em><em>–</em><em>–</em><em>–</em><em>–</em><em>–</em><em>–</em>
First, find the constant of variation <em>k</em> using the formula k=xy.
<em>–</em><em>–––––––</em>
Then, find <em>y</em> if <em>x</em> is equal to four using the formula y=184/x.
<em>F</em><em>i</em><em>n</em><em>a</em><em>l</em><em> </em><em>A</em><em>n</em><em>s</em><em>w</em><em>e</em><em>r</em><em>:</em>
<h2>y = 46</h2>
Answer:
Step-by-step explanation:
The complete question is given thus:
Suppose that computer literacy among people ages 40 and older is being studied and that the accompanying tables describes the probability distribution for four randomly selected people, where x is the number that are computer literate. Is it unusual to find four computer literates among four randomly selected people?
x P(x)
0 0.16
1 0.25
2 0.36
3 0.15
4 0.08
ANSWER:
The odds that this will occur according to the chart are 0.08, or 8%, so although this is unlikely, it's not terribly unusual.
⇒ NO
So from the following we can say it is not unusual to find four (4) computer literates among four randomly selected people.
ok, so P(1) + P(2) + P(3) + P(4) + P(0) = 0.16+0.25+0.36+0.15+0.08 = 1
Whereas the chance of finding four (4) out of four (4) computer iteration is low when compared to other factors.
cheers i hope this helped !!
