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Semmy [17]
2 years ago
11

Meenu bought two fans for ₹1200 each. She sold one at a loss of 5% and the other at a profit of 10%. Find the selling price of e

ach. Also find the total price of loss. ​
Mathematics
1 answer:
Vinvika [58]2 years ago
4 0
<h3><u>Solution: </u></h3>

Overall<u> </u>CP of each fan = ₹1200 .

One is sold at a loss of 5% .

  • ( This means if CP is ₹100, SP is ₹95 ) .

• Therefore,When CP is ₹1200 , Then SP is ₹ 1140.

=  >  \frac{95}{100}  \times 1200 = 1140

Also,Second fan is sold at a profit of 10% .

  • It means , If CP is ₹100 , SP is ₹110.

Therefore , When CP is ₹1200 , Then SP is ₹1320.

<u>• We need to find the combined CP and SP to say whether there was an overall profit or Loss.</u><u>.</u>

  • Total CP = ₹ 1200 + ₹ 1200 = ₹ 2400.
  • Total SP = ₹ 1140 + ₹ 1320 = ₹ 2460.

Since total SP > total CP , A profit of ₹ ( 2460 - 2400 ) or ₹60 has been made ..

<h3>Hope this helps you :)</h3>
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Let X denote the length of human pregnancies from conception to birth, where X has a normal distribution with mean of 264 days a
Kaylis [27]

Answer:

Step-by-step explanation:

Hello!

X: length of human pregnancies from conception to birth.

X~N(μ;σ²)

μ= 264 day

σ= 16 day

If the variable of interest has a normal distribution, it's the sample mean, that it is also a variable on its own, has a normal distribution with parameters:

X[bar] ~N(μ;σ²/n)

When calculating a probability of a value of "X" happening it corresponds to use the standard normal: Z= (X[bar]-μ)/σ

When calculating the probability of the sample mean taking a given value, the variance is divided by the sample size. The standard normal distribution to use is Z= (X[bar]-μ)/(σ/√n)

a. You need to calculate the probability that the sample mean will be less than 260 for a random sample of 15 women.

P(X[bar]<260)= P(Z<(260-264)/(16/√15))= P(Z<-0.97)= 0.16602

b. P(X[bar]>b)= 0.05

You need to find the value of X[bar] that has above it 5% of the distribution and 95% below.

P(X[bar]≤b)= 0.95

P(Z≤(b-μ)/(σ/√n))= 0.95

The value of Z that accumulates 0.95 of probability is Z= 1.648

Now we reverse the standardization to reach the value of pregnancy length:

1.648= (b-264)/(16/√15)

1.648*(16/√15)= b-264

b= [1.648*(16/√15)]+264

b= 270.81 days

c. Now the sample taken is of 7 women and you need to calculate the probability of the sample mean of the length of pregnancy lies between 1800 and 1900 days.

Symbolically:

P(1800≤X[bar]≤1900) = P(X[bar]≤1900) - P(X[bar]≤1800)

P(Z≤(1900-264)/(16/√7)) - P(Z≤(1800-264)/(16/√7))

P(Z≤270.53) - P(Z≤253.99)= 1 - 1 = 0

d. P(X[bar]>270)= 0.1151

P(Z>(270-264)/(16/√n))= 0.1151

P(Z≤(270-264)/(16/√n))= 1 - 0.1151

P(Z≤6/(16/√n))= 0.8849

With the information of the cumulated probability you can reach the value of Z and clear the sample size needed:

P(Z≤1.200)= 0.8849

Z= \frac{X[bar]-Mu}{Sigma/\sqrt{n} }

Z*(Sigma/\sqrt{n} )= (X[bar]-Mu)

(Sigma/\sqrt{n} )= \frac{(X[bar]-Mu)}{Z}

Sigma= \frac{(X[bar]-Mu)}{Z}*\sqrt{n}

Sigma*(\frac{Z}{(X[bar]-Mu)})= \sqrt{n}

n = (Sigma*(\frac{Z}{(X[bar]-Mu)}))^2

n = (16*(\frac{1.2}{(270-264)}))^2

n= 10.24 ≅ 11 pregnant women.

I hope it helps!

6 0
2 years ago
What is 5 5/7 * 5 5/7​
hichkok12 [17]

Answer:

1600/49

Step-by-step explanation:

5 5/7 = 40/7

40/7 * 40/7 = 1600/49

7 0
3 years ago
If a point in the figure below is chosen at random, what is the probability that it is in the shaded region?​
Xelga [282]

Answer:

254/324 which is about 78.4%

Step-by-step explanation:

found area of entire square to be 18² or 324

found area of 4-quarter circles - which equals one circle with radius of 9

A = 81π which is about 70

subtracted 324 and 70 to get 254

ratio of shaded to unshaded is 254 : 324

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Vikki [24]

Answer:

120%

Step-by-step explanation:

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Irina18 [472]

Answer:

y =  -  \frac{13}{9}  +  \frac{4}{9} x

Step-by-step explanation:

4x - 9y = 13

4x - 9y - 4x = 13 - 4x

- 9y = 13 - 4x

y = 9y \div (9) = (13 - 4x) \div ( - 9)

y = (13 - 4x) \div( - 9)

y = 13 \div ( - 9) - 4x \div ( - 9)

y =  - 13 \div 9 - 4x \div ( - 9)

y =  -  \frac{13}{9}  - 4x \div ( - 9)

y =  -  \frac{13}{9}  + 4x \div 9

\boxed{\green{y =  -  \frac{13}{9}  +  \frac{4}{9} x, x E R}}

8 0
3 years ago
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