Answer = d
using the 30 - 60 - 90 triangle theorem
side across from the angle
across from angle 30 is x
across from angle 60 is x rad. 3
across from 90 is 2x
BC is across from angle 60
so BC is the x rad 3
set the given measurement equal to it
x sqrt 3 = 5
÷ sqrt 3 ÷ sqrt 3
x = (5/ sqrt 3)
multiply top and bottom by the radical to get rid of the radical in the bottom
x = (5/ sqrt 3) × (sqrt 3/sqrt 3)
x = 5 sqrt 3/ 3
since side BC is x
BC = 5 sqrt 3/ 3
* Drawing the triangle diagram would help*
Answer:
52 units.
Step-by-step explanation:
If we drop a perpendicular line from point C to AD and call the point ( on AD) E we have a right triangle CED.
Now CE = 6 and as the whole figure is symmetrical about the dashed line,
ED = (26 - 10)/2
= 8.
So by Pythagoras:
CD^2 = 6^2 + 8^2 = 100
CD = 10.
So, as AB = CD,
the perimeter = 10 + 26 + 2(8)
= 52.
Answer:
7(b^2 -2)(b^2 +2)
Step-by-step explanation:
Factoring the common factor 7 from both terms, you get the difference of squares. That can also be factored.
v = 7(b^4 -4) = 7(b^2 -2)(b^2 +2)
The difference b^2-2 will have irrational factors, so does not meet the problem requirements. This is the factorization over integers.
