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s344n2d4d5 [400]
3 years ago
6

Vint is testing ceiling fans in a factory. For one of the tests, he switches the fan on, and after it attains a maximum speed of

500 rotations per minute (rpm), he switches the fan back off, recording the amount of time it takes for the fan to completely stop spinning. The given equation models Vint's test, where x represents time in seconds and y represents the speed in rotations per minute. The equation has been graphed as shown.
Assuming that the test was complete when the fan stopped spinning completely, how long was the test?

A. 100 seconds

B. 10 seconds

C. 20 seconds

D. 500 seconds

Mathematics
2 answers:
Natasha_Volkova [10]3 years ago
8 0

Answer:

20 seconds

Step-by-step explanation:

Given :

y=-5x^2+100x

Where x  represents time in seconds and y represents the speed in rotations per minute.

To Find : Assuming that the test was complete when the fan stopped spinning completely, how long was the test?

Solution:

Since we are supposed to find how long will it take to stop the fan completely

We assumed that  test was complete when the fan stopped spinning completely

i.e. y = Speed = 0

So, Substitute y = 0 in the equation    y=-5x^2+100x

⇒0=-5x^2+100x

⇒5x^2=100x

⇒5x=100

⇒x=\frac{100}{5}

⇒x=20

Thus it took 20 seconds to stop the fan

Hence the test was 20 seconds long.

Gennadij [26K]3 years ago
5 0

Answer:

C. 20 seconds

Step-by-step explanation:

We want to know when y=0

The first y is when it started and the second y=0 is when it stops

Looking at the graph y=0 at x=0 and  y=0 at x=20

The fan started at time 0 and stopped at 20 seconds

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Answer:

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Step-by-step explanation:

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Considering only the values of β for which sinβtanβsecβcotβ is defined, which of the following expressions is equivalent to sinβ
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Answer:

\tan(\beta)

Step-by-step explanation:

For many of these identities, it is helpful to convert everything to sine and cosine, see what cancels, and then work to build out to something.  If you have options that you're building toward, aim toward one of them.

{\tan(\theta)}={\dfrac{\sin(\theta)}{\cos(\theta)}    and   {\sec(\theta)}={\dfrac{1}{\cos(\theta)}

Recall the following reciprocal identity:

\cot(\theta)=\dfrac{1}{\tan(\theta)}=\dfrac{1}{ \left ( \dfrac{\sin(\theta)}{\cos(\theta)} \right )} =\dfrac{\cos(\theta)}{\sin(\theta)}

So, the original expression can be written in terms of only sines and cosines:

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\sin(\beta) * \dfrac{\sin(\beta) }{\cos(\beta) } * \dfrac{1 }{\cos(\beta) } * \dfrac{\cos(\beta) } {\sin(\beta) }

\sin(\beta) * \dfrac{\sin(\beta) \!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{---}}{\cos(\beta) \!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{---}} * \dfrac{1 }{\cos(\beta) } * \dfrac{\cos(\beta) \!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{---}} {\sin(\beta) \!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!{---}}

\sin(\beta) *\dfrac{1 }{\cos(\beta) }

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Working toward one of the answers provided, this is the tangent function.


The one caveat is that the original expression also was undefined for values of beta that caused the sine function to be zero, whereas this simplified function is only undefined for values of beta where the cosine is equal to zero.  However, the questions states that we are only considering values for which the original expression is defined, so, excluding those values of beta, the original expression is equivalent to \tan(\beta).

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Step-by-step explanation:

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