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Natali [406]
3 years ago
10

Find the constant of variation for the relationship shown in the following table: x 1 2 3 4 y 3 6 9 12

Mathematics
2 answers:
stepan [7]3 years ago
7 0

Answer:

y=3x ( the'=' sign is the proportionality sign)

Step-by-step explanation:

x = 1 , 2 , 3 , 4

y = 3 , 6 , 9 , 12

You are multiplying by 3 to get to y

1 x 3 = 3

2 x 3 = 6

3 x 3 = 9

4 x 3 = 12

nasty-shy [4]3 years ago
7 0

well the table would look like this

     x      y

     1      3

     2      6

     3      9

     4      12

and the direct variation is y=3x but the constant of variation is k=3

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Jimmy invests $2500 in an account with a 5% interest rate, making no other deposits or withdrawals. What will Jimmy’s account ba
Alik [6]

Answer:

We conclude that the total amount accrued, principal plus interest,  from compound interest on an original principal of  $2500 at a rate of 5% per year compounded 6 times per year over 8 years is $3723.38.

Step-by-step explanation:

Given

Principle P = $2500

Interest rate r = 5% = 0.05

Time period t = 8 years

To determine

Accrue Amount A = ?

Using the compound interest equation

A\:=\:P\left(1\:+\:\frac{r}{n}\right)^{nt}

where:

A represents the Accrue Amount

P represents the Principal Amount

r represents the interest rate

t represents the time period in years

n represents the number of compounding periods per unit t

Important tip:

  • Given that the interest is compounded 6 times each year, therefore, the value of n = 6.

now substituting P = 2500, r = 0.05, t = 8 and n = 6 in the equation

A\:=\:P\left(1\:+\:\frac{r}{n}\right)^{nt}

A=2500\left(1+\frac{0.05}{6}\right)^{\left(6\right)\left(8\right)}

\:A=2500\left(1+\frac{0.05}{6}\right)^{48}

A=2500\times 1.48935      ∵  \left(1+\frac{0.05}{6}\right)^{48\:\:}=1.48935

A=\:3723.38 $

Therefore, we conclude that the total amount accrued, principal plus interest,  from compound interest on an original principal of  $2500 at a rate of 5% per year compounded 6 times per year over 8 years is $3723.38.

8 0
3 years ago
What is the slope of a line that is perpendicular to a line whose equation is 3y=−4x+2 ?
vova2212 [387]

we know that

if two lines are perpendicular, then the product of their slopes is equal to minus one

so

m1*m2=-1

Step 1

<u>Find the slope of the given line</u>

we have

3y=-4x+2

Solve for y

Divide by 3 both sides

3y/3=(-4x+2)/3

y=-\frac{4}{3}x+ \frac{2}{3}

the slope of the given line is m1=-\frac{4}{3}

Step 2

<u>Find the slope  of a line that is perpendicular to the given line</u>

we have

m1=-\frac{4}{3}

m1*m2=-1

m2=-1/m1

substitute the value of m1

m2=-1/(-4/3)=\frac{3}{4}

therefore

<u>the answer is</u>

the slope is \frac{3}{4}

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