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3 years ago

5. A 200 pound person weighs 33 pounds on the moon.

Mathematics

1 answer:

blsea [12.9K]3 years ago

6 0

Answer:

Well the formula for that is,

weight on Earth(in this case 200)/9.81m/s2) * 1.622m/s2 which comes out to 33

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Please help i’m crying and throwing up

dsp73

Answer:

C. 90

Step-by-step explanation:

mark it brainliest if it helps you ❤️

3 0

2 years ago

A recent study asked U. S. Adults to name 10 historic events that occurred during their lifetime that have had the greatest impa

Nadusha1986 [10]

Using the z-distribution, as we are working with a proportion, it is found that the 99% confidence interval for the proportion of all U. S. Adults who would include the 9/11 attacks on their list of 10 historic events is (0.7458, 0.7942). It means that we are 99% sure that the true proportion for all U.S. adults is between these two bounds.

<h3>What is a confidence interval of proportions?</h3>

A confidence interval of proportions is given by:

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which:

$\pi$ is the sample proportion.

z is the critical value.

n is the sample size.

In this problem, the parameters are:

$z = 2.575, n = 2000, \pi = 0.77$

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.77 - 2.575\sqrt{\frac{0.77(0.23)}{2000}} = 0.7458$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.77 + 2.575\sqrt{\frac{0.77(0.23)}{2000}} = 0.7942$

The 99% confidence interval for the proportion of all U. S. Adults who would include the 9/11 attacks on their list of 10 historic events is (0.7458, 0.7942). It means that we are 99% sure that the true proportion for all U.S. adults is between these two bounds.

More can be learned about the z-distribution at brainly.com/question/25890103

7 0

2 years ago

a grandmother says her grandson is two years older than her granddaughter and that together, they are at least 12 years old. how

vfiekz [6]

Hello There!

As for this problem, we would have to set up an equation in order to determine the missing age. We would do this because we want to find the missing age and by setting up an equation it will help find the age easier, as opposed to manually calculating it. With that said, let's begin to solve.

First, we would create an equation based on what the question says, which would look as:

x + x + 2 = 12

2x + 2 = 12

Subtract two from both sides.

2x = 10

The grand daughter is 5 years old and since the grandson is two years older he is 7.

Thus,

The age of the granddaughter is 5

The age of the grandson is 7

7 0

3 years ago

I) 54,2 X 94= ?

CaHeK987 [17]

Answer:

I) 54.2 X 94 = 5094.8

J) 36.39 X 28 = 1018.92

K) 43.73 X 74.4 = 3253.512

5 0

3 years ago

Read 2 more answers

Devon records 4 hours of reality shows on her DVR she records comedy shows for 3/8 of that amount of time. Devon watches all the

Alenkinab [10]

The number of half-hour sittings needed to watch all the shows by Devon is 11

<u>Solution:</u>

Given, Devon records 4 hours of reality shows on her DVR

she records comedy shows for 3/8 of that amount of time.

$\rightarrow \frac{3}{8} \text { of } 4 \text { hours } \rightarrow \frac{3}{8} \times 4 \rightarrow \frac{3}{2} \text { hours }$

Devon watches all the reality and comedy shows in half-hour sittings.

We have to find the number of half-hour sittings needed to watch all the shows

Now, number of half hour sittings is given as

$=\frac{\text { total time of videos }}{\text { time for hlaf hour sitting }}$

$\begin{array}{l}{=\frac{4 \text { hours for reality shows }+\frac{3}{2} \text { hours for comedy shows }}{\frac{1}{2} \text { hours for each sitting }}} \\\\ {=\frac{4+\frac{3}{2}}{\frac{1}{2}}=\frac{\frac{8+3}{2}}{\frac{1}{2}}=\frac{\frac{11}{2}}{\frac{1}{2}}=\frac{11}{2} \times \frac{2}{1}=11}\end{array}$

Hence Devon needs 11 sittings

3 0

3 years ago