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cluponka [151]
4 years ago
6

State which is greater (6-8)x10 or 6-(8x10)

Mathematics
1 answer:
slava [35]4 years ago
6 0

(6-8)x10is the greatest

Step-by-step explanation:

(6-8)x10= -20

6-(8x10)= -74

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4y=-16-7x equation 1. substitute equation 1 in given equation. 7x(-16-7x)=-16. -112x-49x=-26
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True or False. The cross section of a Sphere is an ellipse.<br>a. True <br>b. False​
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Find the missing side lengths. Leave your answers as radicals in simplest form.
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Answer:

A.

x = \frac{7\sqrt{6}{3}

y = \frac{7\sqrt{6}}{3}

Step-by-step explanation:

Reference angle = 60°

Opposite = \frac{7\sqrt{2}}{2}

Hypotenuse = x

Adjacent = y

✔️To find x, apply the trigonometric function SOH:

Sin 60° = Opp/Hyp

sin 60° = \frac{\frac{7\sqrt{2}}{2}}{x}

\frac{\sqrt{3}}{2} = \frac{\frac{7\sqrt{2}}{2}}{x} (sin 60 = √3/2)

\frac{\sqrt{3}}{2} = \frac{7\sqrt{2}}{2}*\frac{1}{x}

\frac{\sqrt{3}}{2} = \frac{7\sqrt{2}}{2x}

Cross multiply

\sqrt{3}*2x = 7\sqrt{2}*2

2\sqrt{3}*x = 14\sqrt{2}

Divide both sides by 2

\sqrt{3}*x = 7\sqrt{2}

Divide both sides by √3

x = \frac{7\sqrt{2}}{\sqrt{3}}

Rationalize

x = \frac{7\sqrt{2}*\sqrt{3}}{\sqrt{3}*\sqrt{3}}

x = \frac{7\sqrt{6}{3}

✔️To find y, apply the trigonometric function TOA:

Tan 60° = Opp/Adjacent

Tan 60° = \frac{\frac{7\sqrt{2}}{2}}{y}

\sqrt{3} = \frac{\frac{7\sqrt{2}}{2}}{y} (tan 60 = √3)

\sqrt{3} = \frac{7\sqrt{2}}{2}*\frac{1}{y}

\sqrt{3} = \frac{7\sqrt{2}}{2y}

Cross multiply

\sqrt{3}*2y = 7\sqrt{2}

2\sqrt{3}*y = 7\sqrt{2}

Divide both sides by √3

y = \frac{7\sqrt{2}}{\sqrt{3}}

Rationalize

y = \frac{7\sqrt{2}*\sqrt{3}}{\sqrt{3}*\sqrt{3}}

y = \frac{7\sqrt{6}}{3}

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3 years ago
What is b less than 9 in algebraic expression
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8<9

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