The horizontal distance between Carl and the rock at sea is approximately 60.62ft.
Data;
- Angle = 30 degree
- Opposite = 35
- Adjacent = x
<h3>Trigonometric Ratio</h3>
Given the angle of depression from his point to the sea, we can use trigonometric ratio to calculate for the horizontal distance from his location to the bottom of the sea.
SOHCAHTOA
Since we have the value of angle and opposite and we need to calculate the adjacent side of the right-angle triangle, we can use the tangent of the angle to this effect.
The horizontal distance between Carl and the rock at sea is approximately 60.62ft.
Learn more on trigonometric ratio here;
brainly.com/question/12172664
To answer this, let the 3 sides of the regular sized rectangular box be x, y, and z.
When we double all the sides, the new sides have lengths 2x, 2y, and 2z, respectively.
Since the regular box (with dimensions x,y, and z) have 750 toothpicks, we can write
Similarly we can write for the jumbo box as,
which is equal to 
So this is 8 times the original of 
. Hence the jumbo box will have 8 times 750 number of toothpicks.
ANSWER: 
toothpicks
Answer:
B (1,2)
Step-by-step explanation:
Answer:
X = 9 and Y = 8
Step-by-step explanation:
We are to find the midpoint of the coordinates (13,15) and (5,1).
Using the midpoint formula;
M(X, Y) = [(x1+x2)/2, (y1+y2)/2]
X = (x1+x2)/2
Y = (y1+y2)/2
From the coordinates, x1 = 13, y1 = 15, x2 = 5 and y2 = 1
X = 13+5/2
X = 18/2
X = 9
Similarly;
Y = 15+1/2
Y = 16/2
Y = 8
Hence The Tourist Information Center is located at point X = 9 and Y = 8
