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Zarrin [17]
4 years ago
13

⦁ Evaluate ⦁ 6! ⦁ 8P5 ⦁ 12C4

Mathematics
2 answers:
lisabon 2012 [21]4 years ago
7 0
6! = 6 * 5 *4*3*2*1 =720

8p5 = 8*7*6*5*4 = 6720

12C4 = (12p4)/4! = (12*11*10*9)/4*3*2*1 = 495
Vesnalui [34]4 years ago
6 0
N! = n(n-1)(n-2)(n-3)....
∴6! = 6×5×4×3×2×1 = 720
⁸P₅ = \frac{8!}{(8-5)!} =  \frac{8*7*6*5*4*3*2*1}{3*2*1} = 6720
¹²C₄ = \frac{12!}{4!*(12-4)!} =  \frac{12*11*10*9*8*7*6*5*4*3*2*1}{4!*8!}
       = \frac{12*11*10*9*8*7*6*5*4*3*2*1}{4*3*2*1*8*7*6*5*4*3*2*1} = 495

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Step-by-step explanation:

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svetlana [45]

Answer:

A: This polynomial has a degree of 2 , so the equation 12x2+5x−2=0 has two or fewer roots.

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Step-by-step explanation:

f(x) = 12x^2 + 5x - 2.

Since this is a quadratic equation, or a polynomial of second degree, one can easily conclude that this equation will have at most 2 roots. At most 2 roots mean that the function can have either 2 roots at maximum or less than 2 roots. Therefore, in the A category, 2nd option is the correct answer (This polynomial has a degree of 2 , so the equation 12x^2 + 5x − 2 = 0 has two or fewer roots).

To find the roots of f(x), set f(x) = 0. Therefore:

12x^2 + 5x - 2 = 0. Solving the question using the mid term breaking method shows that 12*2=24. The factors of 24 whose difference is 5 are 8 and 3. Therefore:

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(4x-1)(3x+2) = 0.

4x-1 = 0 or 3x+2 = 0.

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It can be seen that f(x) has two distinct real roots. Therefore, in the B category, 1st Option is the correct answer (The quadratic equation 12x2+5x−2=0 has two real solutions, x=−2/3 or x=1/4 , and therefore has two real roots)!!!

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