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HACTEHA [7]
3 years ago
15

Mr. Maddox asked four students to create a number line to help find the sum of fractions 3 2/3 + 1 3/4 + 2/3

Mathematics
2 answers:
makvit [3.9K]3 years ago
5 0
The answer is 6.08..........
balu736 [363]3 years ago
3 0

Answer with explanation:

Question asked by Mr.Maddox to find the sum of fractions with the help of number line :

    \rightarrow 3 \frac{2}{3}+1 \frac{3}{4}+\frac{2}{3}\\\\ \text{Using Associative Property}\\\\\rightarrow a+(b+c)=(b+c)+a\\\\\rightarrow [\frac{2}{3}+ 1\frac{3}{4}]+3 \frac{2}{3}\\\\\rightarrow [\frac{2}{3}+\frac{7}{4}]+\frac{11}{3}\\\\\rightarrow \frac{21+8}{12}+ \frac{11}{3}\\\\\rightarrow\frac{29+44}{12}\\\\ \rightarrow\frac{73}{12}\\\\\rightarrow 6\frac{1}{12}

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A manufacturer knows that their items have a normally distributed length, with a mean of 13.1 inches, and standard deviation of
Afina-wow [57]

Answer:

0.73% probability that their mean length is less than 11.1 inches

Step-by-step explanation:

To solve this question, we have to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation, which is also called standard error s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 13.1, \sigma = 4.1, n = 25, s = \frac{4.1}{\sqrt{25}} = 0.82

What is the probability that their mean length is less than 11.1 inches

This is the pvalue of Z when X = 11.1. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{11.1 - 13.1}{0.82}

Z = -2.44

Z = -2.44 has a pvalue of 0.0073.

0.73% probability that their mean length is less than 11.1 inches

3 0
4 years ago
Can someone please answer this i will give brainliest if i can
Daniel [21]

Answer:

For bag C

Step-by-step explanation:

Bag C has more blue marbles than red ones

5 0
3 years ago
This one too!!! This is from the same project that I was struggling with and was similar to the other problem but I couldn't fig
evablogger [386]

9514 1404 393

Answer:

  y = 1/4x^1 -x -4

Step-by-step explanation:

Same question as previous parts. The working is identical, using different numbers.

Focus-vertex distance is (y-difference) p = -4-(-5) = 1. Vertex is (h, k) = (2, -5). Putting these values into the vertex form and expanding to standard form, you get ...

  y = (1/(4p))(x -h)^2 +k

  y = 1/4(x -2)^2 -5 . . . . . . . . fill in the values for p, h, k

  y = 1/4(x^2 -4x +4) -5 . . . .  expand the square

  y = 1/4x^2 -x +1 -5 . . . . . . . use the distributive property to eliminate parens

  y = 1/4x^1 -x -4 . . . . . . . . . collect terms

_____

Additional information may be found at ...

  brainly.com/question/20338735

6 0
3 years ago
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