Nesreen wants to find out how often people in her town visit the cinema.

The length of the minute hand is 150% of the length of the hour hand. In 2 hours, how much farther does the tip of the minute ha

nekit [7.7K]

The question seems incomplete, as the length of the hour hand isn't given ;

If the tip of the hour hand is taken as 30mm

Answer:

534.1 mm

Step-by-step explanation:

In 2 hours ; cycle performed :

2/ 12

Circumference of a circle = 2 * pi *r

Circumference = 2 * pi * 30 = 60pi

Distance traveled : 60pi * 2/12 = 120pi/ 12 =10pi

The minute hand travels 2 comply cycle in 2 hours

150% taller than short hand :

1.5 * 30 = 45 mm

Distance traveled : 2 (2 * pi * 45) = 180pi

(180pi - 10pi) = 170pi

170π = 534.07075

= 534.1 mm

7 0

3 years ago

The area of a trapezoid is 243cm2. The height is 18cm and the length of one of the parallel sides is 10cm. Find the length of th

Irina18 [472]

Answer:

$Side_2 = 17\ cm$

Step-by-step explanation:

Given

Shape: Trapezoid

$Area = 243cm^2$

$Height = 18cm$

$Side_1 = 10cm$

Required

Determine the length of the second parallel side

The area of a trapezoid is:

$Area = \frac{1}{2}(Side_1 + Side_2) * Height$

Substitute values for Area, Height and Side1

$243 = \frac{1}{2}(10 + Side_2) * 18$

Multiply both sides by 2

$2 * 243 = 2 * \frac{1}{2}(10 + Side_2) * 18$

$486 = (10 + Side_2) * 18$

Divide both sides by 18

$27 = 10 + Side_2$

$Side_2 = 27 - 10$

$Side_2 = 17\ cm$

Hence;

<em>The length of the second parallel side is 17cm</em>

8 0

3 years ago

When is a protractor preferred to a ruler when finding a measurement

Keith_Richards [23]

When measuring an angle.

7 0

2 years ago

What is that shape that is a rectangle but leans on an angle to one side???

jeka94

The answer should be:

Parallelogram

5 0

2 years ago

An eastbound train left at 12pm. Four hours later, a westbound train left the same station. At 8pm, the two trains were 400 mile

Ainat [17]

Answer:

Step-by-step explanation:

Gotta love these motion problems!

d = rt is what we need here to solve this, along with some logic.

If the EB (eastbound) train left at noon then at the end of its travels, at 8pm to be specific, it was traveling for 8 hours. Therefore, for the EB train, t = 8.

If the WB train left at 4 pm then at the end of its travels, also at 8pm, it was traveling for 4 hours. Therefore, for the WB train, t = 4.

The distance between the trains is given as 400 miles. That 400 mile distance is due to the fact that each train traveled a distance of rate*time. The distance the WB train traveled + the distance the EB train traveled = 400 miles. Now we just need to find out the distance each traveled in its respective time frame.

For the EB train. We already know that t = 8. We do not know how fast it's going, so rate is just r. In the distance formula, d = rt:

$d_{EB}=8r$

For the WB train. We already know that t = 4. We do not know this rate either, but we do know that it is traveling 10 mph faster than the EB train, so rate is r + 10. In the distance formula, d = rt:

$d_{WB}=4(r+10)$ and