Answer:
84 ounces of pure gold
Step-by-step explanation:
Jess has 60 ounces of an alloy that is 40% gold. How many ounces of pure gold must be added to this alloy to create a new alloy that is 75% gold?
Pure gold = 100% gold
Let the number of ounces of pure gold = x
Hence, we have the equation
40% × 60 ounces + 100%× x ounces = 75%(60 + x)ounces
= 0.4 × 60 + 1x = 0.75(60 + x)
= 24 + x = 45 + 0.75x
Collect like terms
x - 0.75x = 45 - 24
0.25x = 21
x = 21/0.25
x = 84 ounces
Therefore, we need 84 ounces of pure gold
1/36 + 1/49 = 81 is the standard eq following the formula 1/a.a + 1/b.b = 1/r.r
9,250 is the answer i believe
<h3>
Answer: 24/25</h3>
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Explanation:
If sin(x) = 3/5, then cos(x) = 4/5 through the use of the trig identity
sin^2(x) + cos^2(x) = 1
This is assuming that x is in quadrant Q1.
Plug those values into the identity below and simplify.
sin(2x) = 2*sin(x)*cos(x)
sin(2x) = 2*(3/5)*(4/5)
sin(2x) = 24/25
We know that
side AB is parallel to side CD
then
∠A=∠D
∠B=∠C
therefore
(2x+6)/10=(x+6)/8-------------> 8*(2x+6)=10*(x+6)------> 16x+48=10x+60
16x-10x=60-48----------> 6x=12---------> x=2
so
AE=2x+6-------> 2*2+6--------> AE=10
the answer is AE=10 units
