The difference between 2 times x and y is less than or equal to 1
2 answers:
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Answer:
Step-by-step explanation:
(3x^2+x-1)(x^4-2x+1)
=3x^6-6x^3+3x^2+x^5-2x^2+x-x^4+2x-1
=3x^6+x^5-x^4-6x^3+x^2+3x-1
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