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GarryVolchara [31]
3 years ago
15

Josephine has nine chemistry books, three history books, and eight statistics books. She wants to choose one book of each type t

o study. In how many ways can she choose the three books?
Mathematics
1 answer:
ikadub [295]3 years ago
7 0

Answer:

20

Step-by-step explanation: add them all together

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Please help me with this
Zolol [24]

Answer:

MN=9.1 cm

LM= 9.9 cm

Step-by-step explanation:

3 0
2 years ago
A part-time house cleaner made $9258.13 last year. If he claimed himself as an exemption for $3650 and had a $5700 standard dedu
kari74 [83]

Once we sort through the tax terms, that's just

9258.13 - 3650 - 5700 = $ -91.87
A negative numbers mean the deduction and exemption sheltered all of his income, so he has $0 taxable income, choice D.


3 0
2 years ago
Read 2 more answers
A climber is standing at the top of Mount Kilimanjaro, approximately 3.7 mi above sea level. The radius of the Earth is 3959 mi.
RoseWind [281]
We are given
height = 3.7 mi
radius = 3959 mi

We are asked for the distance between the man and the horizon
The straight line from the man to the horizon is a tangent line to the surface of the earth
Using Pythagorean theorem
(3.7 + 3959)² = 3959² + d²

Solve for d
d = 171 mi
6 0
3 years ago
Read 2 more answers
What will you get if you cut a triangle perpendiculary
swat32

Answer:

2 triangles ?

Step-by-step explanation:

sorry if i got this wrong, when you cut it through the middle connecting the ends it give you two triangles?

3 0
3 years ago
Read 2 more answers
Which of the following expressions is equivalent to a3 + b3?
lubasha [3.4K]
ANSWER
{a}^{3}  + {b}^{3} = (a + b)( {a}^{2 }  - ab +  {b}^{2} )


EXPLANATION

To find the expression that is equivalent to
{a}^{3}  + {b}^{3}
we must first expand
{(a + b)}^{3}
Then we rearrange to find the required expression.


So let's get started.


{(a + b)}^{3}  = (a + b) {(a + b)}^{2}

We expand the parenthesis on the right hand side to get,



{(a + b)}^{3}  = (a + b) ( {a}^{2} + 2ab +  {b}^{2}  )



We expand again to obtain,

{(a + b)}^{3}  =  {a}^{3}  + 3 {a}^{2}b + 3a {b}^{2}   +  {b}^{3}


Let us group the cubed terms on the right hand side to get,

{(a + b)}^{3}  =  {a}^{3}   +  {b}^{3}  + 3 {a}^{2}b + 3a {b}^{2}




{(a + b)}^{3}  =  {a}^{3}   +  {b}^{3}  + 3ab (a+ b)





We make the cubed terms the subject,

{(a + b)}^{3}  - 3ab (a+ b) =  {a}^{3}   +  {b}^{3}

We factor to get,


(a + b)({(a + b)}^{2}  - 3ab ) =  {a}^{3}   +  {b}^{3}


We expand the bracket on the left hand side to get,

(a + b)( {a}^{2}  + 2ab +  {b}^{2}   - 3ab ) =  {a}^{3}   +  {b}^{3}


We finally simplify to get,

(a + b)( {a}^{2}   - ab +  {b}^{2}  ) =  {a}^{3}   +  {b}^{3}
5 0
3 years ago
Read 2 more answers
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