Question

A bag contains x blue chips and y red chips. If the probability of selecting a red chip at random is 3/7, then x/y = ________.A. 7/11B. 3/4C. 7/4D. 4/3E. 11/7

Answer 1

Answer:

D. $\frac{4}{3}$

Step-by-step explanation:

We have been given that a bag contains x blue chips and y red chips. The probability of selecting a red chip at random is 3/7. We are asked to find the $\frac{x}{y}$.

$\text{Probability}=\frac{\text{Number of favorable outcomes}}{\text{Total number of possible outcomes}}$

$P(\text{Red})=\frac{\text{Number of red chips}}{\text{Total number of chips}}$

$P(\text{Red})=\frac{y}{x+y}$

Since we are told that probability of selecting a red chip at random is 3/7, so red balls are 3 and total balls are 7:

$P(\text{Red})=\frac{3}{x+3}$

Since total balls are 7, so we will get:

$x+3=7\\x=4$

Upon substituting $x=4\text{ and } y=3$ in expression $\frac{x}{y}$, we will get:

$\frac{4}{3}$

Therefore, the value of $\frac{x}{y}$ is $\frac{4}{3}$ and option D is the correct choice.