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Stolb23 [73]
3 years ago
8

Kimberly drives at a rate of 50 miles per hour on her trip across the country. If it takes Kimberly 200 gallons of gasoline to d

rive 500 miles, how many minutes will it take her to use x gallons of gasoline if she uses gasoline at the same average rate of consumption?
1. 20x
2. 3/x
3. x/20
4. 3x
Mathematics
1 answer:
ipn [44]3 years ago
3 0

Answer:

3x

Step-by-step explanation:

50 mi/hr × (1 hr / 60 min) × (200 gal / 500 mi) = ⅓ gal/min

(⅓ gal/min) × (t min) = x gal

t = 3x

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The measure of an angle is 61°. What is the measure of its supplementary angle?​
MrMuchimi

Answer:

119°

Step-by-step explanation:

if sum of two angles=180,then they are supplementary.

61+x=180

x=180-61=119

5 0
3 years ago
This data set gives the scores of 41 students on a biology exam: {66, 67, 67, 68, 80, 81, 81, 82, 22, 65, 66, 68, 69, 70, 71, 71
Naddika [18.5K]
I think the answer is 74.
3 0
3 years ago
The table shows the change in the water level (in centimeters) of a reservoir for three months. Find the total change in the wat
RideAnS [48]

Answer:

-\frac{65}{28} or -2\frac{9}{28}

Step-by-step explanation:

Add all fractions:

-1\frac{3}{4} + -\frac{1}{28} + -\frac{15}{28} = -\frac{65}{28}

Simplify if needed:

-\frac{65}{28} = -2\frac{9}{28}

5 0
2 years ago
The position of an object at time t is given by s(t) = 6 - 14t. Find the instantaneous velocity at t = 6 by finding the derivati
nikdorinn [45]

Answer:

<em>It results -14 in either way</em>

Step-by-step explanation:

<u>Velocity As A Rate Of Change </u>

The velocity of an object can be computed as the rate of change of its displacement (or position taken as a vector) over time. If we compute it as a derivative, it's called instantaneous velocity, and if computed as the slope of the function (difference quotient) at a certain point it's the average velocity

The position of the object as a function of time is

\displaystyle s(t)=6-14t

Computing the derivative

\displaystyle s'(t)=-14

We can see it's a constant value. If we use the slope or rate of change:

\displaystyle v=\frac{s_2-s_1}{t_2-t_1}

Now let's fix two values for time  

\displaystyle t_1=5\ sec,\ t_2=8\ sec

and compute the corresponding positions, by using the given function

\displaystyle s_1=6-14(5)=-64

\displaystyle s_2=6-14(8)=-106

Now we compute the average velocity

\displaystyle v=\frac{-106-(-64)}{8-5}

\displaystyle v=\frac{-106+64}{3}=\frac{-42}{3}

\displaystyle v=-14

We get the very same result in both ways to compute v. It happens because the position is related with time as a linear function, it's called a constant velocity motion.

7 0
3 years ago
Please tell me the answer and help me explain how it’s the right answer
Gala2k [10]
Answer: number greater than -8 includes -2, 1/4, 2.6, 4

Explanation:


3 0
3 years ago
Read 2 more answers
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