Answer:
12km/h
Step-by-step explana:
Let's call the total distance 2a from which we can calculate t1 equivalent to the first half of the distance a/10 similar to t2 is a/15 from which the total time is a/6 . We have the average speed equal to the total distance dduowcngf divided by the total inferred time by 2a/(a/6) which equals 12km/h
Let the width be "x" cm.
Then the length is "x+12" cm
And the area = x(x+12) = x^2+12x cm^2
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Change the dimensions:
width = "x-2" cm
length = "x+10" cm
New area = (x-2)(x+10) = x^2 + 8x - 20 cm^2
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Equations :
Old area - New area = 108 cm^2
x^2+12x -(x^2 + 8x - 20) = 108
4x + 20 = 108
4x = 88
x = 22 cm (original width)
x+12 = 24 cm (original length)
(-1,4) this should be the correct answer if im not mistakin if im wrong im sorry'
The ratio is 2:1. They could be resaigned to 8 meters and 4 meters.
