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MrMuchimi
3 years ago
9

K={(2, 1), (3, 2), (4, 1), (5,3)} Is K-1 a function and why?

Mathematics
1 answer:
Ostrovityanka [42]3 years ago
6 0
No each element in the domain does not have one range value
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Does anybody know this ?
Aleonysh [2.5K]

Answer:

0, 1, 2, 3, 4

Step-by-step explanation:

Multiply each x value by 1/3 then add 2. Since the numerator is 1, you would multipy by one and divide by the denominator of 3, so you really need to divide each x value by 3 then add 2.

-6:

-6/3 = -2

-2 + 2 = 0

-3:

-3/3 = -1

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0:

0/3 = 0

0 + 2 = 2

3:

3/3 = 1

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6:

6/3 = 2

2 + 2 =4

5 0
2 years ago
What is the product?
Sonja [21]
3/22 is the answer in simplest form
6 0
4 years ago
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Colt1911 [192]
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5 0
3 years ago
Trigonometry question foundation
Elden [556K]

Answer:

56.9

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4 0
3 years ago
You are given a rectangular sheet of cardboard that measures 11 in. by 8.5 in. (see the diagram below). A small square of the sa
GaryK [48]

Answer:

Terrence's

Step-by-step explanation:

The length of the square that will be cut out is the height of the box.

1. a

Anya's method: 8.5 -1.5 =7, 11- 1.5 =9.5, the height is 1.5, so the volume is height x length x width which is 1.5 x 9.5 x 7 =99.75 squared inches.

Terrence's method: 8.5-3 = 5.5, 11-3 = 8. Vol= 5.5 x 8 x 3 =132 squared inches. 99.75 < 132 squared inches, Terrence's idea would create larger volume.

1. b

The box's size depends on the length/width/height of the cardboard being cut, which is why different measurements / cutting methods for the same size cardboard can result in different box sizes.

2. The square would be cut from all four corners, therefore the sum of the 2 squares on the cardboard cannot exceed the short side of the cardboard. The shorter side of the cardboard is 8.5 inches, divided by 2 = 4.25 inches, hence the squares cannot  be larger than 4.25 inches. Keep in mind that if you cut exactly 4.25 inches you will have a strip of 2.5 inches width that cannot be turned into a box.

If you want to cut 5 inches squares out, depending on how you draw it, it would either overlap or go outside of the paper because 5+5 is ten, surely on the 11 inches side that would still be perfectly fine but for the 8.5 inches side, there isn't any room for the 10 inches.

7 0
3 years ago
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