1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
wel
3 years ago
11

How can you use models to estimate percent questions?

Mathematics
1 answer:
Colt1911 [192]3 years ago
5 0
You can use models to estimate percent questions by estimating the locations of 50%, 75%, 40%, 6%, and 65% on the model.. 

You might be interested in
Maggie bought 3 dozen muffins from a baker for $48. Find the costs of 1 dozen muffins and 9 dozen muffins.
Gennadij [26K]
We will say that d = 1 dozen. and y = cost

we know that 3 dozen is 48. so
3d = 48.

to get the cost of 1d, we have to get the 3 to change into a 1. the only way to do this is to divide 3 by 3. if we divided the left side by 3 we must also do the right so:
3d = 48
1d = 16

so 1 dozen = 16

to change 3d into 9d we have to multiply by 3. we again have to do this to both sides. so:
3d = 48
9d = 144
7 0
3 years ago
Maria bought seven boxes. a week later half of all her boxes were destroyed in fire
Kay [80]

Answer:ok

Step-by-step explanation:

Ok

3 0
3 years ago
Read 2 more answers
In 2002, the Centers for Disease Control and Prevention (CDC) reported that 8% of women married for the first time by their 18th
ehidna [41]

Question:

In 2002, the Centers for Disease Control and Prevention (CDC) reported that 8% of women married for the first time by their 18th birthday, 25% married by their 20th birthday, and 76% married by their 30th birthday. Based on these data, what is the probability that in a family with two daughters, the first and second daughter will be married by the following ages? (Enter your answers to four decimal places.) (a) 18 years of age (b) 20 years of age (c) 30 years of age

Answer:

A.) 0.0064

B.) 0.0625

C.) 0.5776

Step-by-step explanation:

Given the following :

Married by 18th birthday = 8% = 0.08

Married by 20th birthday = 25% = 0.25

Married by 30th birthday = 76% = 0.76

In a family with two(2) daughters :

P(First daughter will be married by 18) = 0.08

P(second daughter will be married by 18) = 0.08

P(1st and 2nd married by 18) = (0.08×0.08) = 0.0064

B.)

P(First daughter will be married by 20) = 0.25

P(second daughter will be married by 20) = 0.25

P(1st and 2nd married by 20) = (0.25×0.25) = 0.0625

C.)

P(First daughter will be married by 30) = 0.76

P(second daughter will be married by 30) = 0.76

P(1st and 2nd married by 30) = (0.76×0.76) = 0.5776

6 0
2 years ago
Drag each set of side lengths to show whether they can or cannot make a triangle, or if there is not enough information to tell.
Svetach [21]

Answer:

D and E

Step-by-step explanation:

because the rule to make triangle is

a<b+c with a, b and c is the side of the triangle

6 0
3 years ago
Simplify:<br> 3x+1b+10g-4x
Aneli [31]

Answer:

b+10g-x

Step-by-step explanation:

3x-4x=x

New equation becomes:

b+10g-x

4 0
2 years ago
Read 2 more answers
Other questions:
  • How do you answer this question y=-3x+4 and y=3x-2 with transitive property of equation
    13·1 answer
  • The vertex of a parabola is (-1.5, -12.5), and its y-intercept is (0, -8).
    10·2 answers
  • Given that we have already tossed a balanced coin ten times and obtained zero heads, what is the probability that we must toss i
    9·1 answer
  • The scatterplot that represents the monthly values of stock QRS has an r
    10·1 answer
  • The sum of two odd numbers is 42. They are both prime numbers, and the difference of the two numbers is 16. What are the two num
    5·2 answers
  • I don’t understand this at all helppp
    9·1 answer
  • Step by step solution
    6·1 answer
  • 1/3+2/6 Plz And Thank You
    5·2 answers
  • The figure below is a square inside a rectangle
    15·1 answer
  • Please help meee! Math makes my brain hurt :(
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!