1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Nataly_w [17]
3 years ago
5

The University College is interested in the average number of hours per week that freshmen spend going to parties. They took a r

andom sample of 300 freshmen and calculated a mean of 6 hours a week going to parties and a 95% confidence interval for the population mean to be 4 to 8 hours a week. Based on this information, what was their standard error of the mean?
Mathematics
1 answer:
tekilochka [14]3 years ago
5 0

Answer:

And the confidence interval is given by:

4 \leq \mu \leq 8

We can estimate the margin of error like this:

ME = \frac{8-4}{2}= 2

And the margin of error is given by:

ME=z_{\alpha/2} SE

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.025,0,1)".And we see that z_{\alpha/2}=1.96

And solving for the standard error we got:

SE= \frac{2}{1.96}= 1.02

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean for the sample  

\mu population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm z_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

And the confidence interval is given by:

4 \leq \mu \leq 8

We can estimate the margin of error like this:

ME = \frac{8-4}{2}= 2

And the margin of error is given by:

ME=z_{\alpha/2} SE

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.025,0,1)".And we see that z_{\alpha/2}=1.96

And solving for the standard error we got:

SE= \frac{2}{1.96}= 1.02

You might be interested in
Help ASAP and pls tell me how thanks
bulgar [2K]
I have no clue ooooo mmmmyyyyy goooshhhh
6 0
3 years ago
Please please help I’ll give the brain thing if you help but you need to have a correct answer + explain thanks :)))
Alecsey [184]

Answer:

i really dont know im in 7th grade im so sorry

Step-by-step explanation:

7 0
2 years ago
15-2x=-7x what does x equal
Degger [83]

Answer:

x = -3

Step-by-step explanation:

15 - 2x = -7x

add 2x

15 = -5x

divide by -5

-3 = x

4 0
3 years ago
A state is considering license plates that have two digits followed by four letters. Assuming no combinations are excluded, how
love history [14]

Answer:

32,292,000

Step-by-step explanation:

In your question, it asks how many license plate combinations we could make WITHOUT repeats.

We need some prior knowledge to answer this question.

We know that:

  • There are 26 letters in the alphabet
  • We can make 10 digits (0 - 9)

With the information we know above, we can solve the question.

Since we CAN'T have repeats, we would be excluding a letter or number for each license plate.

We're going to need to multiply each "section" in order to find how many combinations of license plates we can make.

We decrease by one letter and one number in each section since we can't have repeats.

Now, we can solve.

Work:

26*25*24*23*10*9 = 32,292,000

When you're done multiplying, you should get 32,292,000.

This means that there could be 32,292,000 different combinations of license plates.

<h3>I hope this helps you out.</h3><h3>Good luck on your academics.</h3><h3>Have a fantastic day!</h3>
8 0
3 years ago
Read 2 more answers
PLEASE ANSWER! WILL MARK BRAINLIEST!!
lord [1]

Answer:

Here you go.Hope this help!!

5 0
2 years ago
Read 2 more answers
Other questions:
  • What is the sixth multiple of 1/5
    14·1 answer
  • What are they?<br> Equal Lines?<br> Parallel Lines?<br> perpendicular Lines?<br> None of the above?
    11·1 answer
  • Please answer!
    5·2 answers
  • What is the value of h(-7)?<br><br> h(x) = [3x] - 1<br><br> A. 22<br> B. -20<br> C. -22<br> D. 20
    8·2 answers
  • a woodworker wants to cut a board that is 6.432 feet long into 4 equal-length pieces. How long will each of the cut boards be?
    14·1 answer
  • What is -7 = x/2 + 1
    7·1 answer
  • Determine weather the function shown in the graph is even or odd.....will give brainlest
    15·1 answer
  • Simplify 8(7x – 1) + 4(x + 5).
    13·2 answers
  • Someone please explain to me how to do this ‼️
    10·1 answer
  • Please help me asap :(
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!