Answer:
The function, f(x) to model the value of the van can be expressed as follows;

Step-by-step explanation:
From the question, we have;
The amount at which Amrita bought the new delivery van, PV = $32,500
The annual rate of depreciation of the van, r = -12% per year
The Future Value, f(x), of the van after x years of ownership can be given according to the following formula

Therefore, the function, f(x) to model the value of the van after 'x' years of ownership can be expressed as follows;

Answer:
4/7
Step-by-step explanation:
Number of Blue vans = 4
Number of white vans = 3
Total number of vans = Number of Blue vans + Number of white vans
= 4 + 3
= 7 vans
Number of blue vans : Number of white vans = 4 : 3
Fraction of vans that are blue = Number of Blue vans / Total number of vans
= 4 / 7
Fraction of vans that are blue = 4/7
Answer:
88.46%
Step-by-step explanation:
433 - 383 = 50
50 ÷ 433 = 0.1154
0.1154 x 100 = 11.54%
100% - 11.54% = 88.46%
<u>Check work:</u>
433 x 88.46% = 383
Answer:
The probability that a randomly chosen Ford truck runs out of gas before it has gone 325 miles is 0.0062.
Step-by-step explanation:
Let <em>X</em> = the number of miles Ford trucks can go on one tank of gas.
The random variable <em>X</em> is normally distributed with mean, <em>μ</em> = 350 miles and standard deviation, <em>σ</em> = 10 miles.
If the Ford truck runs out of gas before it has gone 325 miles it implies that the truck has traveled less than 325 miles.
Compute the value of P (X < 325) as follows:

Thus, the probability that a randomly chosen Ford truck runs out of gas before it has gone 325 miles is 0.0062.