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Burka [1]
4 years ago
6

If r=10 and s=31 find R. Round to the nearest tenth

Mathematics
2 answers:
Natasha2012 [34]4 years ago
6 0

<u>Answer:</u>

The correct answer option is C. 17.9°.

<u>Step-by-step explanation:</u>

We are given a right angled triangle, SRT, with two known sides, r and s.

We are to find the measure of the angle R.

For that, we will use tan.

tan R = \frac { r } { s }

tan R = \frac { 1 0 } { 3 1 }

R = tan' 0.322

R = 17.9°

Vsevolod [243]4 years ago
3 0

Answer: option c.

Step-by-step explanation:

You need to remember the identity:

tan\alpha=\frac{opposite}{adjacent}

The inverse of the tangent function is arctangent. You need to use this to calculate the angle "R":

 \alpha =arctan(\frac{opposite}{adjacent})

You know that you need to find the measure of "R" and r=10 (which is the opposite side) and s=31 (which is the adjacent side), you can sustitute values into \alpha =arctan(\frac{opposite}{adjacent})

Then, you get:

R=arctan(\frac{10}{31})\\\\R=17.9\°

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Accourding to one of the circle equations, \displaystyle (x - h)^2 + (y - k)^2 = r^2,the centre of the circle is represented by \displaystyle (h, k).Moreover, all negative symbols give you the OPPOCITE TERMS OF WHAT THEY <em>REALLY</em> ARE, so you must pay cloce attention to which term gets which symbol. Another thing you need to know is that the radius will ALWAYS be squared, so no matter how your equation comes about, make sure that the radius is squared. Now, in case you did not know how to define the radius, you can choose between either method:

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\displaystyle \sqrt{[-x_1 + x_2]^2 + [-y_1 + y_2]^2} = d \\ \\ \sqrt{[-7 + 4]^2 + [-2 - 2]^2} = r \hookrightarrow \sqrt{[-3]^2 + [-4]^2} = r \hookrightarrow \sqrt{9 + 16} = r; \sqrt{25} = r \\ \\ \boxed{5 = r}

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I am joyous to assist you at any time.

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