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qaws [65]
3 years ago
15

X2 + X-8 What is the degree

Mathematics
1 answer:
icang [17]3 years ago
8 0

Answer:

1

Step-by-step explanation:

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Find the smallest value of k such that the LCM of<br> k and 6 is 60
Advocard [28]

Answer: The smallest valuest value for<em> k </em>is 10, such that LCM o<em>f k</em> and 6 is 60.

Step-by-step explanation:

We know that, LCM = Least common multiple.

For example : LACM of 12 and 60  is 60.

If LCM of k and 6 is 60.

i.e. the least common multiple of k and 6 is 60.

Since, 10 x 6 = 60.

The smallest valuest value for<em> k </em>should be 10, such that LCM o<em>f k</em> and 6 is 60.

Hence, the smallest value of k is 10.

5 0
3 years ago
FUNDRAISING A school is raising money by selling calendars for $20 each. Mrs. Hawkins promised a party to whichever of her Engli
____ [38]

Rj, this is the solution to question 19:

• 1st period class sold 60 calendars in total

,

• 2nd period class sold 123 calendars in total

We calculate the average per week, this way:

• 1st period class sold 60/4 = 15 calendars per week

,

• 2nd period class sold 123/4 = 30.75 calendars per week

In consequence the multiplication equation that represents this situation is:

15w + 30.75w = 183, where w is the number of weeks Mrs. Hawkins' classes sold calendars.

This is the solution to question 20:

We already know the average number of calendars that 1st and 2nd period classes sold per week. Now, let's calculate the average for 3nd 4th peiod classes, this way:

• 3rd period class sold 89 calendars in total

,

• 4th period class sold 126 calendars in total

Therefore, the average is:

• 3rd period class sold 89/4 = 22.25 calendars per week

,

• 4th period class sold 126/4 = 31.5 calendars per week

Summarizing, we have:

15 + 30.75 + 22.25 + 31.5 = 99.5 calendars was the average number sold by all her classes in a week.

•

7 0
1 year ago
Area= 60 cm width 5cm what is the length and width
Anna [14]

Answer:

length = 12 cm | width = 5 cm

Step-by-step explanation:

You already know the width is 5 cm. So now just divide 5 from 60 to get the length of 12 cm.

3 0
3 years ago
Read 2 more answers
The wading pool shown is a trapezoidal prism with a total volume of 286 cubic feet. What is the missing dimension? First base: 8
harkovskaia [24]
To find the missing dimension you will use the formula for finding the volume of a prism and solve for the missing dimension.  In this case 2ft is how deep the pool is and you will solve for the width of the pool.

V = Bh, where B is the area of the base.  In this case, use the area of a trapezoid formula.

286 = 1/2h(8 +13)2
<u>286</u> = <u>21h</u>
21      21
h = 13.6

The width of the wading pool is approximately 13.6 feet.
5 0
3 years ago
Help me with Thai math it’s worth 22 points PLZZ answer ALL of them
joja [24]

Answer:

  1. supply (B)
  2. A step in process (A)
  3. (b)
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5 0
2 years ago
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