Answer:
look below but sorry that i dont know part b
Step-by-step explanation:
y = 5/2x-3
slope=5/2 y-int = -3
y=x-9
slope=1/1 y-int=-9
y=5x
slope= 5/1 y int=0
y=-1/2x +5
slope=-1/2 y-int= 5
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Answer:
about 252.78 ft
Step-by-step explanation:
Define angle QMP as α. Then ...
MN = 60·sin(α)
NP = 60·cos(α)
area MPN = (1/2)(MN)(NP) = 1800sin(α)cos(α)
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PQ = 60tan(α)
area MPQ = (1/2)(MP)(PQ) = 1800tan(α)
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The ratio of areas is 2.5, so we have ...
1800tan(α) = 2.5·1800sin(α)cos(α)
1 = 2.5cos(α)² . . . . . . divide by 1800tan(α)
cos(α) = √0.4 . . . . . . solve for cos(α)
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Then the perimeter is ...
Perimeter = MN +NP +PQ +QM = 60sin(α) +60cos(α) +60tan(α) +60/cos(α)
= 60(sin(α) +cos(α) +tan(α) +sec(α))
= 60(0.774597 +0.632456 +1.224745 +1.581139)
= 60(4.212936) = 252.776
The perimeter of the trapezoid is about 252.776 feet.
_____
With perhaps a little more trouble, you can find the exact value to be ...
perimeter = (6√10)(7+√6+√15)
Answer:
Picture #1: x=16 ; y=10
Picture #2: x=21 ; y=15
Picture #3: x=18
Step-by-step explanation:
Picture #1:
(8x-14)* and (5x+34)* are Alternate Exterior Angle so they are congruent. And (8x-14)* and (5y+16)* are supplementary so they equal 180*.
Picture #2:
(6x+7)* and (3x-16)* are supplementary so they equal 180*. And (6x+7)* and (11y-32)* are Vertical Angles so they are congruent.
Picture #3:
(7x-6)* and (4x-7)* are supplementary so they equal 180*.
Answer:23
Step-by-step explanation:
Answer: 105 miles
Step-by-step explanation:
You can write an equation for this problem and solve it.
32 miles=1/3x-3, where x is equal to the total length of the highway.
35=1/3x, and then you multiply by 3, to get x=105
