The correct answer to the question is C).Dry ice changes to carbon dioxide when kept in an open container.
EXPLANATION:
Before answering this question, first we have to understand sublimation.
Sublimation is a thermal process of state or phase change in which solid substance is directly converted into gas without melting i.e the substance won't undergo liquid state.
In the given question, dry ice is given. Dry ice is the solid state of carbon dioxide. When the dry ice changes to carbon dioxide, directly solid carbon dioxide is converted into gaseous carbon dioxide. No liquid carbon dioxide is formed . So, the phase change is from solid to gas.
Hence, the conversion of dry ice into carbon dioxide is an example of sublimation.
Answer:
a = 129.663 ![rad/s^{2}](https://tex.z-dn.net/?f=rad%2Fs%5E%7B2%7D)
Explanation:
We know that:
T = Ia
Where T is the torque, I is the moment of inertia and a is the angular aceleration:
First, we will find the moment of inertia using the following equation:
I = ![\frac{1}{2}MR^2](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7DMR%5E2)
Where M is the mass and R is the radius of the disk. Replacing values, we get:
I = ![\frac{1}{2}(1.29kg)(1.184m)^2](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%281.29kg%29%281.184m%29%5E2)
I = 0.904 kg*m^2
Second, we will find the torque using the following equation:
T = (
)*(R)
Where
is the force on one side and
is the force on the other side. Replacing values, we get:
T = (162N-63N)(1.184m)
T = 117.216N*m
Finally, we replace T and I on the initial equation as:
T = Ia
117.216N = (0.904)(a)
Solving for a:
a = 129.663 ![rad/s^{2}](https://tex.z-dn.net/?f=rad%2Fs%5E%7B2%7D)
Answer:
<em>The Answer to question 14 is : glycerol (n=1.47)</em>
Answer:
θ = 34.77°
Explanation:
From diffraction equation:
![m\lambda = dSin\theta](https://tex.z-dn.net/?f=m%5Clambda%20%3D%20dSin%5Ctheta)
where,
m = order of diffraction
λ = wavelength of light used
d = slit separation
θ = angle
Therefore, for initial case:
m = 2
λ = 600 nm = 6 x 10⁻⁷ m
d = slit seperation = ?
θ = angle 20°
Therefore,
![(2)(6\ x\ 10^{-7}\ m)=d(Sin\ 20^o)\\\\d = \frac{12\ x 10^{-7}\ m}{0.342}\\\\d = 3.5\ x\ 10^{-6}\ m](https://tex.z-dn.net/?f=%282%29%286%5C%20x%5C%2010%5E%7B-7%7D%5C%20m%29%3Dd%28Sin%5C%2020%5Eo%29%5C%5C%5C%5Cd%20%3D%20%5Cfrac%7B12%5C%20x%2010%5E%7B-7%7D%5C%20m%7D%7B0.342%7D%5C%5C%5C%5Cd%20%3D%203.5%5C%20x%5C%2010%5E%7B-6%7D%5C%20m)
Now, for the second case:
m = 5
λ = 600 nm = 6 x 10⁻⁷ m
d = slit seperation = (1.5)(3.5 x 10⁻⁶ m) = 5.26 x 10⁻⁶ m
θ = angle = ?
Therefore,
![(5)(6\ x\ 10^{-6}\ m) = (5.26\ x\ 10^{-6}\ m)Sin\theta\\\\Sin\theta = \frac{(5)(6\ x\ 10^{-7}\ m)}{(5.26\ x\ 10^{-6}\ m)}\\\\\theta = Sin^{-1}(0.5703)](https://tex.z-dn.net/?f=%285%29%286%5C%20x%5C%2010%5E%7B-6%7D%5C%20m%29%20%3D%20%285.26%5C%20x%5C%2010%5E%7B-6%7D%5C%20m%29Sin%5Ctheta%5C%5C%5C%5CSin%5Ctheta%20%3D%20%5Cfrac%7B%285%29%286%5C%20x%5C%2010%5E%7B-7%7D%5C%20m%29%7D%7B%285.26%5C%20x%5C%2010%5E%7B-6%7D%5C%20m%29%7D%5C%5C%5C%5C%5Ctheta%20%3D%20Sin%5E%7B-1%7D%280.5703%29)
<u>θ = 34.77°</u>
the spine is divided into four main regions: cervical, thoracic, lumbar and sacral.
Have an amazing day! <3