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shutvik [7]
3 years ago
11

Name two or the four common boundary conditions set when discussing gravitational potential energy?

Physics
1 answer:
Vikentia [17]3 years ago
3 0

Answer:

I only know one

Explanation:

The strength of the gravitational field.

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A woman wearing athletic clothing outside. The woman is stretching her legs in a lunge position. Based on the nonverbal messages
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Answer:

D

Explanation:

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How does newton's second law describe the motion of an object?
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Answer:

Newton's second law of motion can be formally stated as follows: The acceleration of an object as produced by a net force is directly proportional to the magnitude of the net force, in the same direction as the net force, and inversely proportional to the mass of the object.

Explanation:

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Which of the following is true about a planet orbiting a star in uniform circular motion? A. The direction of the velocity vecto
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3 years ago
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You and a friend each carry a 15 kg suitcase up two flights of stairs, walking at a constant speed. Take each suitcase to be the
AlekseyPX

Answer:

Both of you did the same work but you expended more power.

Explanation:              

<em>Work done</em> by an object is calculated by force applied multiplied by the distance.

  W=F*d

From the figure given below let us calculate force applied bith you and yopur friend.

Let us take the stairs in positive x direction,

Work done by you W₁ ,

The force applied Fₓ = F - mgsinθ =maₓ

here aₓ = 0, because both of you move with constant speed

F - mgsinθ = 0

F=  mgsinθ

The work done by you on the suitcase is

W = F L cos0°  ,    where L is he length of the staircase.

W = FL = mgsinθL ,  by substituting value of F

Work done by you is W₁ = mgLsinθ

Similarly work done by your friend is W₂ = mgLsinθ.

Because both of you carry suitcase of same weight and in staircase is in same angle the force applied is same .

Therefore <em>work done by both of you is same</em> . Both of you did equal work.

The power , is defined as amount of energy converted or transfered per second or rate at which work is done .

P =\frac{W}{t} =\frac{FL}{t}

Power spend by you P₁ = mgLsinθ/t

P₁ = 15*9.8*Lsinθ/30

P₁ = 4.9L sinθ  eqn 1

Power spend by your friend is P₂ = mgLsinθ/t

P₂ =15*9.8*Lsinθ/60

P₂ = 2.45Lsinθ    eqn 2

Dividing eqn 1 and eqn 2

P₁ = 2P₂

You have spend more power than your friend .

Hence Both of you did equal work but you spend more power.

7 0
3 years ago
A 1500-W electric heater is plugged into the outlet of a 120-V circuit that has a 20-A circuit breaker. You plug an electric hai
tekilochka [14]

Answer:

900 W.      

Explanation:

Given that

Electric heater 1500 W

We know that power P given as

P= V I

So the total power of 120 V and 20 A circuit

P = 120 x 20

P= 2400 W

So the power new load P'

P'= Total system power(P)- Electric heater load

P ' = 2400 - 1500

P'= 900 W

So the answer is 900 W.

6 0
3 years ago
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