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shutvik [7]
3 years ago
11

Name two or the four common boundary conditions set when discussing gravitational potential energy?

Physics
1 answer:
Vikentia [17]3 years ago
3 0

Answer:

I only know one

Explanation:

The strength of the gravitational field.

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What is the difference between transverse waves and longitudinal waves?
Degger [83]

D.transverse waves move perpendicular and longitudinal waves move parallel to the direction of energy movement..

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At the nose of a missile in flight, the pressure and temperature are 5.6 atm and 850°R, respectively. Calculate the density and
Contact [7]

To solve this problem we will apply the definition of the ideal gas equation, where we will clear the density variable. In turn, the specific volume is the inverse of the density, so once the first term has been completed, we will simply proceed to divide it by 1. According to the definition of 1 atmosphere, this is equivalent in the English system to

1atm = 2116lb/ft^2

The ideal gas equation said us that,

PV = nRT

Here,

P = pressure

V = Volume

R = Gas ideal constant

T = Temperature

n = Amount of substance (at this case the mass)

Then

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The amount of substance per volume is the density, then

\rho = \frac{P}{RT}

Replacing with our values,

\rho = \frac{5.6*2116}{1716*850}

\rho = 0.00812slug/ft^3

Finally the specific volume would be

v = \frac{1}{\rho}

v = 123ft^3/slug

6 0
3 years ago
Numeria
Vinil7 [7]

Answer:

hope it helps

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5 0
3 years ago
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Suppose that two point charges, each with a charge of +1.00 C, are separated by a distance of 1.0 m. If the distance between the
Aleksandr-060686 [28]

Given:

The magnitude of each charge is q1 = q2 = 1 C

The distance between them is r = 1 m

To find the force when distance is doubled.

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The new distance is

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The force can be calculated by the formula

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Here, k is the constant whose value is

k=9\times10^9\text{ N m}^2\text{ /C}^2

On substituting the values, the force will be

\begin{gathered} F=9\times10^9\times\frac{1\times1}{(2)^2} \\ =2.25\times10^9\text{ N} \end{gathered}

7 0
1 year ago
the value of acceleration due to gravity option A is same on equator and poles option B is list on poles option C is list on equ
stiks02 [169]

Answer:

D. Increases from pole to equator

Explanation:

I majored in Science

8 0
3 years ago
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