Disregarding air friction, what force(s) act on a bullet shot from a rifle as it moves through the air?
1 answer:
The gravity.
In fact, the gravity will "pull" the bullet towards the ground, and the magnitude of the force is equal to the weight of the bullet:
where
m is the mass of the bullet
is the acceleration of gravity
Due to the presence of this force, the bullet will have a parabolic motion, which consists of two independent motions on the horizontal axis and on the vertical axis:
- on the horizontal axis, the bullet moves by uniform motion with constant speed
- on the vertical axis, the bullet moves by uniformly accelerated motion, with constant acceleration g towards the ground.
In fact, the gravity will "pull" the bullet towards the ground, and the magnitude of the force is equal to the weight of the bullet:
where
m is the mass of the bullet
Due to the presence of this force, the bullet will have a parabolic motion, which consists of two independent motions on the horizontal axis and on the vertical axis:
- on the horizontal axis, the bullet moves by uniform motion with constant speed
- on the vertical axis, the bullet moves by uniformly accelerated motion, with constant acceleration g towards the ground.
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Answer: 2.068*m
Explanation: According to work energy-theorem , the workdone in accelerating the electron equals the energy it would give off in terms of light.
workdone= qV
energy = hc/λ
q=magnitude of an electronic charge= 1.602*
h= planck constant = 6.626*
c= speed of light =2.998*
v= potential difference= 6*
λ= wavelength=unknown
by making λ subject of formulae we have that
λ=
λ = 6.626* * 2.998*
/ 1.602*
* 6*
λ =
by doing the necessary calculations, we have that
λ = 2.068*m