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viva [34]
3 years ago
15

Drag the tiles to the correct boxes to complete the pairs.

Mathematics
1 answer:
sineoko [7]3 years ago
3 0

Answer:

The percentage of hatchbacks that run on gasoline: 78%

The percentage of diesel vehicles that are hatchbacks: 21 %

Step-by-step explanation:

The given table represents the following:

Hatchbacks that run on Gasoline = 18

Hatchbacks that run on Diesel = 5

Total number of hatchbacks = 23

Sedan that run on Gasoline = 15

Sedans that run on Diesel = 12

Total number of sedans = 27

SUVs that run on Gasoline = 3

SUVs that run on Diesel = 7

Total number of SUVs = 23

Total number of gasoline vehicles = 36

Total number of Diesel vehicles = 24

To find:

the percentage of hatchbacks that run on gasoline

the percentage of diesel vehicles that are hatchbacks

Solution:

\text{Percentage of hatchbacks that run on gasoline = } \dfrac{\text{Number of hatchbacks on gasoline}}{\text{Total number of hatchbacks}}\times 100\\\Rightarrow \text{Percentage of hatchbacks that run on gasoline = } \dfrac{18}{23}\times 100 \approx 78\%

\text{Percentage of diesel vehicles that are hatchbacks = } \dfrac{\text{Number of hatchbacks that run on diesel}}{\text{Total number of diesel vehicles}}\times 100\\\Rightarrow \text{Percentage of diesel vehicles that are hatchbacks = } \dfrac{5}{24}\times 100 \approx 21\%

So, the answer is:

The percentage of hatchbacks that run on gasoline: <em>78%</em>

The percentage of diesel vehicles that are hatchbacks: <em>21%</em>

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Step-by-step explanation:

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3 years ago
If the mean weight of 4 backfield members on the football team is 221 lb and the mean weight of the 7 other players is 202 lb, w
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Let x_1, x_2, x_3, x_4, x_5, x_6, x_7, x_8, x_9, x_{10}, x_{11} be the weight of i-th player.

1. If the mean weight of 4 backfield members on the football team is 221 lb, then

\dfrac{x_1+x_2+x_3+x_4}{4}=221\ lb.

2. If the mean weight of the 7 other players is 202 lb, then

\dfrac{x_5+x_6+x_7+x_8+x_9+x_{10}+x_{11}}{7}=202\ lb.

3. From the previous statements you have that

x_1+x_2+x_3+x_4=221\cdot 4=884 \lb,\\ \\x_5+x_6+x_7+x_8+x_9+x_{10}+x_{11}=202\cdot 7=1414\ lb.

Add these two equalities and then divide by 11:

x_1+x_2+x_3+x_4+x_5+x_6+x_7+x_8+x_9+x_{10}+x_{11}=884+1414=2298\ lb,\\ \\\dfrac{x_1+x_2+x_3+x_4+x_5+x_6+x_7+x_8+x_9+x_{10}+x_{11}}{11}=\dfrac{2298}{11}=208\dfrac{10}{11}\ lb.

Answer: the mean weight of the 11-person team is 208\dfrac{10}{11}\ lb.

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2 years ago
4-s/12=-6<br> Please help me!!!
Sveta_85 [38]
4-\dfrac{s}{12}=6
\dfrac{s}{12}=-2
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2 years ago
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