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VMariaS [17]
3 years ago
11

What is the sign of 23/45 + -23/45

Mathematics
1 answer:
Paha777 [63]3 years ago
3 0

Answer:

0

Step-by-step explanation:

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Find the distance and midpoint of a segment with the following endpoints: (5,-1) and (-9,-1)
Likurg_2 [28]

Answer:

d = 14

(-2,-1)

General Formulas and Concepts:

  • Order of Operations: BPEMDAS
  • Distance Formula: d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}
  • Midpoint Formula: (\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})

Step-by-step explanation:

<u>Step 1: Define</u>

(5, -1)

(-9, -1)

<u>Step 2: Find distance </u><em><u>d</u></em>

  1. Substitute:                    d = \sqrt{(-9-5)^2+(-1-(-1))^2}
  2. Simplify:                        d = \sqrt{(-9-5)^2+(-1+1)^2}
  3. Subtract/Add:               d = \sqrt{(-14)^2+(0)^2}
  4. Evaluate:                       d = \sqrt{196}
  5. Evaluate:                       d = \14

<u>Step 3: Find Midpoint</u>

  1. Substitute:                    (\frac{5-9}{2},\frac{-1-1}{2})
  2. Subtract:                       (\frac{-4}{2},\frac{-2}{2})
  3. Divide:                          (-2,-1)
7 0
3 years ago
Unsure how to do this calculus, the book isn't explaining it well. Thanks
krok68 [10]

One way to capture the domain of integration is with the set

D = \left\{(x,y) \mid 0 \le x \le 1 \text{ and } -x \le y \le 0\right\}

Then we can write the double integral as the iterated integral

\displaystyle \iint_D \cos(y+x) \, dA = \int_0^1 \int_{-x}^0 \cos(y+x) \, dy \, dx

Compute the integral with respect to y.

\displaystyle \int_{-x}^0 \cos(y+x) \, dy = \sin(y+x)\bigg|_{y=-x}^{y=0} = \sin(0+x) - \sin(-x+x) = \sin(x)

Compute the remaining integral.

\displaystyle \int_0^1 \sin(x) \, dx = -\cos(x) \bigg|_{x=0}^{x=1} = -\cos(1) + \cos(0) = \boxed{1 - \cos(1)}

We could also swap the order of integration variables by writing

D = \left\{(x,y) \mid -1 \le y \le 0 \text{ and } -y \le x \le 1\right\}

and

\displaystyle \iint_D \cos(y+x) \, dA = \int_{-1}^0 \int_{-y}^1 \cos(y+x) \, dx\, dy

and this would have led to the same result.

\displaystyle \int_{-y}^1 \cos(y+x) \, dx = \sin(y+x)\bigg|_{x=-y}^{x=1} = \sin(y+1) - \sin(y-y) = \sin(y+1)

\displaystyle \int_{-1}^0 \sin(y+1) \, dy = -\cos(y+1)\bigg|_{y=-1}^{y=0} = -\cos(0+1) + \cos(-1+1) = 1 - \cos(1)

7 0
1 year ago
How to determine the volume of a cup?​
snow_lady [41]

Answer:

1 to 8  in cups or 1 to 16 in table spoons

Step-by-step explanation:

4 0
3 years ago
4 friends share 3 oranges equally
skad [1K]
Each will get 1.33 orange. 
4 0
3 years ago
Read 2 more answers
How do you write 2.244 million in standard form
tiny-mole [99]
2.244 x 106

or

2,244,000

7 0
3 years ago
Read 2 more answers
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