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Gelneren [198K]
3 years ago
14

This is correct right?

Mathematics
1 answer:
meriva3 years ago
4 0

No, you have to distribute before adding

You distribute it like: 5x3 5x4, to get 15 and 20, then add it together

hope that helps :)

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In a competitive examination negative marks of 2 are awarded for each wrong answers and 4 marks for every correct answer. If nee
Alex777 [14]

9514 1404 393

Answer:

  Rajan gets 6 marks more

Step-by-step explanation:

Neerav's marks are (15)(4) +(5)(-2) = 60 -10 = 50.

Rajan's marks are (14)(4) = 56.

Rajan gets 6 more marks than Neerav.

3 0
3 years ago
Use back-substitution to solve the system of linear equations.
ludmilkaskok [199]

Step-by-step explanation:

x - y + 5z = 29

y + 2z = 4

z = 7

since z = 7 we can use this value in second equation

y + 2×7 = 4 and y = -10

now we know the value of y we can solve the first equation

x -(-10) + 5×7 = 29

x + 10 + 35 = 29

x = -11

5 0
4 years ago
Read 2 more answers
Can anyone help me with this question?
victus00 [196]
It is a

That the answer
3 0
3 years ago
What is happening to this graph when the x-values are between 4 and 8?
Vilka [71]

Answer:

The correct answer is A. It is constant.

Step-by-step explanation:

When the x-values are between 4 and 8, this graph is constant.  This can be seen because the graph is a horizontal line, meaning it has zero slope.  Since the slope is zero, it is neither increasing nor decreasing, and is known as constant.

Hope this helps!

6 0
3 years ago
Need help with this​
Vanyuwa [196]

Answer:

Slope-int form: y = 3x+5

Standard form: y - 3x = 5.

Step-by-step explanation:

(reminder: slope-intercept form is expressed as y=mx+b, and standard form is expressed as ax+bx=c.)

Since the slope is 3, the coefficient of x is also 3, which makes the equation y=3x.

But the y coordinate of the equation at x = -2 is -6, so we need to add 5 to the end of the equation, leaving you with:

y=3x+5.

To convert it to standard form, subtract 3x from both sides:

y - 3x = 5.

I hope this helped you.

4 0
3 years ago
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