P-111
A-90???
I have no clueeeee
We are given :

Step 1: factor the part inside square root
The function given inside square root is of quadratic form.
So let us try to factorise it using AC method.
Here A*C = 4*25 = 100
so we have to find factors of 100 that add up to give -20.
the two factors are -10 and -10.
Rewriting the function :

=
=
=
Step 2:
Now we take square root of the factorised form

= 
Answer : (2x-5)
I think it is 4 cause I love u
Answer:
y=2x-5
Step-by-step explanation:
First simplify: y-1=2x-6
y-1=2(x-3)
First simplify and distribute everything.
<u>y-1=2x-6</u>
So, x equals 2 because it got distributed into the numbers inside the parenthesis. Same with the 2 and -3. They multiplied to become -6.
Since it's y-1=2x-6, you can simplify it even more so the -1 goes to the other side and turns into positive 1.
<u>y - 1 (+ 1) = 2x -6 (+ 1)</u>
-1(+1)=0 which leaves just the variable y on the <em><u>left side</u></em>.
-6(+1)=-5 which leaves 2x-5 on the <em><u>right side</u></em>.
This results in y=2x-5. Hope this helped ;)
Answer:
Arithmetic
An = A[n - 1] + 3/5
An = 3/5[n]
Step-by-step explanation:
Number of days = 5
Number of chocolate = 3
Computation:
Recursive:
Number of chocolate eat per day = 3/5
So,
First term a1 = 3/5
So,
An = A[n - 1] + 3/5
Explicit:
An = 3/5 + 3/5[n-1]
An = 3/5[n]