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Kazeer [188]
3 years ago
12

9 hundreds equals how many tens

Mathematics
2 answers:
qaws [65]3 years ago
3 0

Answer:

90 tens

Step-by-step explanation:

900 = 10x

Variable x refers to how many 10's are needed to equal 900

To solve for this, divide both sides of the equation by 10

900 ÷ 10 = 10x ÷ 10

90 = 1x

90 = x

It will take 90 tens to equal 900

yulyashka [42]3 years ago
3 0
9 hundreds are equal to 90 tens
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The length of a rectangle is twice its width. If the perimeter of the rectangle is 54 in, find its area.
sergiy2304 [10]

Answer: 162 in²

Step-by-step explanation:

The factors of 54 are listed below:

  • 1
  • 2
  • 3
  • 6
  • 9
  • 18
  • 27
  • 54

18 and 9 are the two factors that when plugged into the equation below, equals 54:

l+l+w+w=P

This can also be written as:

(l*2)+(w*2)=P

So now that we have our two factors, we need to multiply them by each other to get our answer.

18 times 9 = 162

Our answer is 162

6 0
2 years ago
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Solve for T:<br><br> R = X - T <br><br> please help Me!!
777dan777 [17]
The answer to the question

3 0
3 years ago
Help please?
Nikolay [14]

Answer:

An angle bisector.

Step-by-step explanation:

This is a ray (Line that extends only one infinitely while the other way has an eventual and perceivable end) that divides an angle (in this case, the angle of a triangle) into two equal parts.

7 0
3 years ago
An exponential function f(x) = ab^xpasses through the points (0, 2) and (3, 54). What are the values of a and
Vsevolod [243]

Answers:

a = 2

b = 3

=======================================================

Explanation:

Plug in x = 0 and y = 2 to find that

y = a*b^x

2 = a*b^0

2 = a*1

2 = a

a = 2

Then plug in x = 3 and y = 54 to determine the value of b

y = a*b^x

y = 2*b^x

54 = 2*b^3

2b^3 = 54

b^3 = 54/2

b^3 = 27

b = (27)^(1/3)

b = 3

So we have y = a*b^x update to y = 2*3^x

7 0
2 years ago
Susie’s Sweet Shop sells chocolate boxes that contain three types of chocolate truffles: solid chocolate truffles, cream center
olganol [36]

Let us make a list of all the details we have

We are given

The cost of each solid chocolate truffle = s

The cost of each cream centre chocolate truffle = c

The cos to each chocolate truffle with nuts = n

The first type of sweet box that contains 5 each of the three types of chocolate truffle costs $41.25

That is 5s+5c+5n = 41.25 (cost of each type of truffle multiplied by their respective costs and all added together)

The second type of sweet box that contains 10 solid chocolate trufles, 5 cream centre truffles and 10 chocolate truffles with nuts cost $68.75

That is 10s+5c+10n = $68.75

The third type of sweet box that contains 24 truffles evenly divided that is 12 each of solid chocolate truffle and chocolate truffle with nuts cost $66.00

That is 12s+12n=$66.00

Hence option C is the right set of equations that will help us solve the values of each chocolate truffle.



6 0
3 years ago
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