Answer:
Infinite solutions.
Step-by-step explanation:
Let's solve your system by substitution.
3y=9x+15;3x−y=−5
Rewrite equations:
3x−y=−5;3y=9x+15
Step: Solve 3x−y=−5 for y:
3x−y=−5
3x−y+−3x=−5+−3x(Add -3x to both sides)
−y=−3x−5
−y −1 −1=−3x−5
(Divide both sides by -1)
y=3x+5
Step: Substitute 3x+5 for y in 3y=9x+15:
3y=9x+15
3(3x+5)=9x+15
9x+15=9x+15(Simplify both sides of the equation)
9x+15+−9x=9x+15+−9x(Add -9x to both sides)
15=15
15+−15=15+−15(Add -15 to both sides)
0=0
Hello lucker
Step-by-step explanation:
