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Airida [17]
3 years ago
5

What is the domain of g?

Mathematics
1 answer:
Mrac [35]3 years ago
7 0

Answer:

Solution. The domain of g(x) consists of all real numbers except x = 32, since that input value would cause us to divide by 0. Likewise, the domain of f consists of all real numbers except 1. So we need to exclude from the domain of g(x) that value of x for which g(x) = 1.

Step-by-step explanation:

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-4 1/2 - 1 1/4 + 1 3/8
professor190 [17]

Answer:

4 3/8

Step-by-step explanation:

8 0
2 years ago
Solve for the right triangle given only one side and angle
34kurt

Answer:

CD = √11 and CE = √11

Step-by-step explanation:

We know that m∠D is 45° (by using the sum of interior angles in a triangle) so therefore, ΔDCE is a 45 - 45 - 90 triangle (the 45, 45, and 90 refer to the angle measures). The ratio of sides in a 45 - 45 - 90 triangle is 1 : 1 : √2 where the 1s are the sides and the √2 is the hypotenuse. We need to solve for x in x : x : √22. If you notice that √22 = √2 * √11, we can use this to find x, therefore, x = 1 * √11 = √11 so CD = √11 and CE = √11.

8 0
3 years ago
Read 2 more answers
Pls answer this! I need to pass!
KengaRu [80]

Answer:

b

Step-by-step explanation:

6 0
3 years ago
ssume that in the year 2000 there are four different forms of psychotherapy available for curing phobias. an experimenter arrang
Liono4ka [1.6K]

We will compare pairwise treatment with the help of t-statistic to find the best treatment.The t-statistic, which is used in statistics, measures how far a parameter's estimated value deviates from its hypothesized value relative to its standard error.We need to check if the treatments are effective in curing phobia.

First, we must determine whether there is a relationship between the type of treatment used and the final result (cure or not cure). We may examine this using the Chi-square test of association.In the second phase, we must determine if all therapies are the same or different if the alternative hypothesis—that is, whether there exists any kind of link between therapy and cure—is accepted.

We must perform a One-way ANOVA for the treatments in this case, assuming that all treatments are equal. If the null hypothesis is rejected in this instance, then the treatments differ. then, we go to step three.We will compare pairwise treatment with the help of t-statistic to find the best treatment.

To learn more about t-statistic visit:brainly.com/question/15236063

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5 0
1 year ago
Need help please help me
ANTONII [103]
Megan:
x to the one third power =  x ^{1/3}
<span>x to the one twelfth power = </span>x ^{1/12}

<span>The quantity of x to the one third power, over x to the one twelfth power is:
</span>\frac{x ^{1/3}}{x ^{1/12}}
<span>
Since </span>\frac{ x^{a} }{ x^{b} } = x ^{a-b}
then \frac{x ^{1/3}}{x ^{1/12}} = x^{1/3-1/12}

Now, just subtract exponents:
1/3 - 1/12 = 4/12 - 1/12 = 3/12 = 1/4

\frac{x ^{1/3}}{x ^{1/12}} = x^{1/3-1/12} = x^{1/4}


Julie:
x times x to the second times x to the fifth = x * x² * x⁵

<span>The thirty second root of the quantity of x times x to the second times x to the fifth is
</span>\sqrt[32]{x* x^{2} * x^{5} }
<span>
Since </span>x^{a}* x^{b}= x^{a+b}
Then \sqrt[32]{x* x^{2} * x^{5} }= \sqrt[32]{ x^{1+2+5} } =\sqrt[32]{ x^{8} }

Since \sqrt[n]{x^{m}} = x^{m/n} }
Then \sqrt[32]{ x^{8} }= x^{8/32} = x^{1/4}

Since both Megan and Julie got the same result, it can be concluded that their expressions are equivalent.
3 0
3 years ago
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