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kvv77 [185]
3 years ago
13

Use the distributive property to rewrite each expression. Then simplify (a+7)2

Mathematics
1 answer:
ASHA 777 [7]3 years ago
8 0

Answer:

2a+14

Step-by-step explanation:

2×a+2×7

2a+14

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Have no idea helppppppppppp
mario62 [17]
Answer: choice A) 7017

==========================================================

Work Shown:

The first term is a_1 = 24 and we go up by 7 each time.
The common difference is d = 7

The nth term formula we'll use is
a_n = a_1 + (n-1)*d
a_n = 24 + (n-1)*7

----------

The 1000th term corresponds to n = 1000

Replace every n with 1000
Then use the order of operations (PEMDAS) to simplify

a_n = 24 + (n-1)*7
a_1000 = 24 + (1000-1)*7
a_1000 = 24 + (999)*7
a_1000 = 24 + 6993
a_1000 = 7017
3 0
3 years ago
Rename 24 ten thousands
NemiM [27]
I'm not sure what you mean by rename
4 0
3 years ago
Help me pleaseee finically algebra please I need help
maxonik [38]

Answer:

$7,367.43

Step-by-step explanation:

6 0
3 years ago
Factor the polynomial: 2x(x - 4) + 7(x-4)
mojhsa [17]

Answer:

(x - 4)(2x + 7)

Step-by-step explanation:

Given

2x(x - 4) + 7(x - 4) ← factor out (x - 4) from each term

= (x - 4)(2x + 7)

7 0
3 years ago
Mauricio divided two identical rectangles into equal parts. He colored one part of each rectangle. What is true about the areas
Ivenika [448]

Answer:

Areas of the colored parts are equal

Step-by-step explanation:

Given Mauricio divided two identical rectangles into equal parts.

Now given Mauricio colored one part of each rectangle. we have to tell about the true statement of colored parts.

Two identical rectangles means the rectangle having equal areas. He divides these two into equal parts and shaded one of each part

Let area of rectangle is x unit^{2}

∴ Colored part area = \frac{1}{2}xunit^{2}  →  (1)

Similarly, other rectangle area identical to above rectangle is  x unit^{2}

∴ Colored part area = \frac{1}{2}xunit^{2}  →   (2)

From above eq (1) and (2), we get

Areas of the colored parts are equal which is equals to \frac{1}{2}xunit^{2}


4 0
3 years ago
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