A group of scientists are studying the effects of different fertilizers on the growth of pea plants. They began their study with
10 pea plants. They gave each plant a different type of fertilizer and tracked their growth over a period of 2 months. The results of this experiment weren’t considered valid by other scientists because there was no control group. Which of the following represents an appropriate control group for this experiment? A. A group of plants that’s not subjected to any fertilizer B. A group of plants that’s subjected to one fertilizer C. A group of plants that’s subjected to all types of fertilizers D. A group of plants that’s subjected to two fertilizers
A. A group of plants that’s not subjected to any fertilizer
Explanation:
In a scientific experiment, a control group is the group that did not receive any of the treatments evaluated in the experiment.
In the experiment shown in the question above, the group of scientists wanted to test the effects of different fertilizers on the growth of 10 pea plants. Each fertilizer represents a treatment that will be tested on the plants, in which case the control group would be a group of plants that were not submitted to any fertilizer.
The control group is important because it serves as a reference standard for the evaluation of variables in other treatments. Without the control group, it is not possible for the experiment to have a credible result.
Based on the scenario being described within the question it can be said that this is an example of resource partitioning. This term refers to when a species divides the limited resources in order to avoid competition within it's environment. Such as the two species of mice are doing by feeding in on the same resources at different times in order to avoid competition and conflict between each other. Thus allowing them to co-exist within the same environment.
Cellular respiration is a cellular process in the metabolism of sugar components to produce metabolites such as lactic acid, acetic acid, aldehydes, and other components. It starts with the cleaving of the sugar component (6-carbon) to 3-carbon components until it becomes pyruvate
