The sum of two integers is 74. The larger is 26 more than twice the smaller.Find the two integers
2 answers:
Answer:
Let two integers be x and y.
Consider x > y
The sum of two integers is 74.
⇒ x+y = 74 .....[1]
It is also given that: The larger is 26 more than twice the smaller
⇒x = 2y +26 ......[2]
Substitute equation [2] into [1] we have;
Combine like terms;
Subtract 26 from both sides we have;
3y = 48
Divide both sides by 3 we have;
y = 16
Substitute the value of y in [2] we have;
x = 2(16)+26 = 32+26
x = 58
Therefore, the two integers are 58 and 16
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Answer:
10
Step-by-step explanation:
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with (x₁, y₁ ) = (2, - 4) and (x₂, y₂ ) = (2, 6)
d = =
=
= 10
For this case we have:
One hundred equals 100
three times fives equals
So, rewriting the expression we have:
Answer:
One hundred divided by the quantity three times fives is equivalent to