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Georgia [21]
3 years ago
8

A conveyor belt carries filled bottles of milk to be packed. The bottles are placed five feet apart on the belt. If the belt is

moving at a rate of two feet per second, how many bottles will be packed in one hour?
Mathematics
1 answer:
nikdorinn [45]3 years ago
8 0

Answer:

1,440 bottles will be packed in an hour

Step-by-step explanation:

Firstly, we need to calculate the Amount of Distance the conveyor belt will move in an hour.

Now the speed with which it moves is 2 feet per seconds. We calculate the number of seconds in a hour= 60 * 60 = 3600 seconds. The total distance is thus 3,600 * 2 = 7,200 ft

Now, to calculate the number of bottles to be packed in an hour, we simply divide the total distance covered by the distance between the bottles = 7,200/5 = 1,440 bottles

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A buyer went to the market to buy strawberries. He purchased 120 randomly selected strawberries from a vendor who claimed that n
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Answer:

z=\frac{0.333 -0.25}{\sqrt{\frac{0.25(1-0.25)}{120}}}=2.10  

p_v =P(z>2.10)=0.018  

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Step-by-step explanation:

Data given and notation

n=120 represent the random sample taken

X=40 represent the number of strawberries damaged

\hat p=\frac{40}{120}=0.333 estimated proportion of strawberries damaged

p_o=0.25 is the value that we want to test

\alpha represent the significance level

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that no more than 25% of his total harvest of strawberries was damaged.:  

Null hypothesis:p\leq 0.25  

Alternative hypothesis:p > 0.25  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.333 -0.25}{\sqrt{\frac{0.25(1-0.25)}{120}}}=2.10  

Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The next step would be calculate the p value for this test.  

Since is a right tailed test the p value would be:  

p_v =P(z>2.10)=0.018  

At 5% of significance we can conclude that the true proportion of strawberries damage is higher than 0.25

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