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Varvara68 [4.7K]
3 years ago
5

What is the algebraic expression for the word phrase "eight times the difference of h and five"?

Mathematics
1 answer:
Serggg [28]3 years ago
3 0

Answer: C

Step-by-step explanation:

eight times : 8*

the difference of h and 5 : (h-5)

eight times the difference of h and five: 8(h-5)

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Please help whoever answers this correctly I'll mark your answer brainliest​
djyliett [7]

Answer: The 2nd and 3rd one are correct

Step-by-step explanation:

After reflecting it, the square itself would not change, only the position of the square. Therefore, the same line segments from the beginning which were given would be parallel.

6 0
2 years ago
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4(2r + 8) = 88<br> I would like to know the answer to this question please
Kamila [148]

4(2r + 8) = 88

mutiply the bracket by 4

(4)(2r)(4)(8)= 8r+32

8r+32= 88

Move +32 to the other side

Sign changes from +32 to -32

8r+32-32= 88-32

8r= 88-32

8r= 56

divide by 8 for both sides

8r/8= 56/8

Cross out 8 and 8, divide by 8. Then becomes r

r= 7

Answer: r= 7

3 0
3 years ago
Evaluate 3{5 + 3[10 + 4 · 8]}
klemol [59]
3 {5 + 3[10 + 4.8]}
3 {5 + 3[ 14.8 ]}
3 {5 + 44.4}
3 {49.4}
148.2
5 0
3 years ago
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The sum of 2x+7 and −x+12 is equal to 14 what is x?
Alekssandra [29.7K]

Answer:-5


Step-by-step explanation:

2x+7-x+12=14

x+19=14

x=-5

                 


4 0
3 years ago
*****PLEASE HELP (30 POINTS)*****
ziro4ka [17]

Answer:

2. C) 21.2 yd    3. B) angle IQL    4. B) 55 degree

Step-by-step explanation:

2. The area of an equilateral triangle is given by,

A = \frac {\sqrt{3} \times a^{2}}{4}------(1)  where a = length of each side.

Here, a = 7 yd

so , putting a = 7 yd in (1) , we get,

A = \frac {\sqrt{3} \times 49}{4}  sq. yd.

  \simeq 21.2 sq. yd.

3. B) angle IQL

4. Let, the centre of the circle be at O,

then, ∠DOB = 105°  and ∠BOC = 145° (given)

so, ∠OBD = \frac{180^{\circ} - \angle DOB}{2}

                = \frac{180^{\circ} - 105^{\circ}}{2}

                = 37.5°  [since the sum of three angles of a triangle  is 180° and OB and OD are two radii of the same circle]

and, similarly, ∠OBC = \frac{180^{\circ} - \angle COB}{2}

                = \frac{180^{\circ} - 145^{\circ}}{2}

                = 17.5° [since the sum of three angles of a triangle  is 180° and OB and OC are two radii of the same circle]

so,  ∠CBD = ∠OBD + ∠OBC

                 = 37.5° + 17.5°

                 = 55°

3 0
4 years ago
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