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Fantom [35]
3 years ago
10

The sum of 2x+7 and −x+12 is equal to 14 what is x?

Mathematics
1 answer:
Alekssandra [29.7K]3 years ago
4 0

Answer:-5


Step-by-step explanation:

2x+7-x+12=14

x+19=14

x=-5

                 


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Given the figure below, find the values of x and z.
nataly862011 [7]
First, because 13x-85 and 97 are across from each other like that, you know that they are equal to each other. If you solve, you know that x is equal to 14. Then, you know that all the angles must equal 360 degrees. If you add 97 and 97 together, you get 194. Now, subtract that by 360, and you get the remaining degrees of the other two angles. Then, divide that by two, and z equals 83. Hope this helped!
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3 years ago
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The side of a square is x, and the area is A. Express A in terms of x. Draw the graph which shows how A depends on x.
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a=x squared or x times itself

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3 years ago
Make ‘w’ the subject.
Romashka-Z-Leto [24]

Answer:

w = (cv +dy) / (cb - ad)

Step-by-step explanation:

Multiply through by c

aw + y = c(bw + v) / d                Multiply by d

d(aw + y) = c(bw + v)                  Remove the brackets

daw + dy = cbw + cv                  Subtract dy from both sides.

daw +dy - dy = cbw + cv -dy

daw = cbw + cv - dy                   Subtract cbw from both sides

daw - cbw = cbw - cbw + cv - dy

daw - cbw = cv -  dy                  Isolate W on the left.

w(da - cb) =  cv - dy                   Divide by cb - ad on both sides.

w = (cv - dy) / (ad - bc)                Answer


6 0
3 years ago
What is the center and radius of the circle given by x2 + y2 - 10x - 12y + 24 = 0?​
AveGali [126]

Answer:

centre (5, 6 ) , r = \sqrt{37}

Step-by-step explanation:

the equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k ) are the coordinates of the centre and r the radius

given

x² + y² - 10x - 12y + 24 = 0 ( collect x and y terms together and subtract 24 from both sides )

x² - 10x + y² - 12y = - 24

using the method of completing the square

add ( half the coefficient of the x / y terms)² to both sides

x² + 2(- 5)x + 25 + y² + 2(- 6)y + 36 = - 24 + 25 + 36

(x - 5)² + (y - 6)² = 37 ← in standard form

with centre (h, k ) = (5, 6 ) and r = \sqrt{37}

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